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2 years ago

Can the ordered pair (1,12) be found on the graph of 35 miles per hour?A. YesB. No

Mathematics

2 answers:

Rina8888 [55]2 years ago

7 0

Answer:

A. Yes

Step-by-step explanation:

aniked [119]2 years ago

6 0

Answer:

Step-by-step explanation:

35 is big

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Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. a

liberstina [14]

First plane: 496x
Second plane: 558( x - 1/2) 

Equation: 496x = 558( x - 1/2) 

Solving x = 9/2 , or x = 4.5 hours.

Hope this helps.

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3 years ago

Find the area of a trapezium ABCD in which AB || CD, AB = 14 cm, CD = 8 cm. Given

adoni [48]

Answer:

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Step-by-step explanation:

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2 years ago

Shortcuts?:) Find dy/dx y=-3x^7

Lostsunrise [7]

Knowing the power rule:
dx*n*x^(n-1) all you'd need to do is bring the 7 down and multiply it by -3, then subtract 1 from 7. Because dx is 1 you don't need to worry about it (you'll use chain rule for that)
So your final answer should be dy/dx= -21x^6

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3 years ago

Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = yzi + 4xzj + ex

natima [27]

Answer:

The result of the integral is 81π

Step-by-step explanation:

We can use Stoke's Theorem to evaluate the given integral, thus we can write first the theorem:

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S$

Finding the curl of F.

Given $F(x,y,z) = < yz, 4xz, e^{xy} >$ we have:

$curl \vec F =\left|\begin{array}{ccc} \hat i &\hat j&\hat k\\ \cfrac{\partial}{\partial x}& \cfrac{\partial}{\partial y}&\cfrac{\partial}{\partial z}\\yz&4xz&e^{xy}\end{array}\right|$

Working with the determinant we get

$curl \vec F = \left( \cfrac{\partial}{\partial y}e^{xy}-\cfrac{\partial}{\partial z}4xz\right) \hat i -\left(\cfrac{\partial}{\partial x}e^{xy}-\cfrac{\partial}{\partial z}yz \right) \hat j + \left(\cfrac{\partial}{\partial x} 4xz-\cfrac{\partial}{\partial y}yz \right) \hat k$

Working with the partial derivatives

$curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(4z-z\right) \hat k\\curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k$

Integrating using Stokes' Theorem

Now that we have the curl we can proceed integrating

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S$

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot \hat n dS$

where the normal to the circle is just $\hat n= \hat k$ since the normal is perpendicular to it, so we get

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S \left(\left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k\right) \cdot \hat k dS$

Only the z-component will not be 0 after that dot product we get

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3z dS$

Since the circle is at z = 3 we can just write

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3(3) dS\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 9\int \int_S dS$

Thus the integral represents the area of a circle, the given circle $x^2+y^2 = 9$ has a radius r = 3, so its area is $A = \pi r^2 = 9\pi$ , so we get

$\displaystyle \int\limits_C \vec F \cdot d\vec r = 9(9\pi)\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 81 \pi$

Thus the result of the integral is 81π

5 0

3 years ago

A football player gains 7 yards, loses 4 yards, and gains 12 yards. Write his gains and losses as integers. If

Alexxx [7]

If he started at 0 where does he end up?

0 + 7 yards - 4 yards + 12 yards = 15 yards
He ends up with 15 yards

Integers are whole numbers.

5 0

3 years ago

Read 2 more answers