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SCORPION-xisa [38]
4 years ago
14

Which measure will help Rita calculate how much the electricity bills vary, on average, from the mean billed amount? The monthly

bills were:
$92, $98, $90, $99, $96, $91, $89, $106, $95, $102, $96, $99.

A.
interquartile range
B.
range
C.
median
D.
mean absolute deviation
Mathematics
2 answers:
Ganezh [65]4 years ago
8 0

Answer:

its d. the mean

Step-by-step explanation:

its right on plato

notsponge [240]4 years ago
7 0

Answer: c


Step-by-step explanation:

because to find the average is to add all your numbers up and to divide them by how many numbers you have

and the median is the finding the middle which is the average you line them up from lowest to greatest value and cross one off from the beginning and one from the end until you are left either one or two values


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What is 3 divided by 4?
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An object is thrown straight up from the top of a building 150 feet tall with an initial velocity of 12 feet per second. The hei
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Answer:

will this work or help ?

Step-by-step explanation:

The given equation governs the height versus time of the object. h(0) = 64, so the ground is considered at h = 0. The question is at what time is h = 0? So, set h = 0 and solve for t.

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6 0
3 years ago
A sample of 66 obese adults was put on a low-carb diet for a year. The average weight loss was 11 pounds and the standard deviat
Illusion [34]

Answer:

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{19}{\sqrt{66}} = 6.02

The lower end of the interval is the sample mean subtracted by M. So it is 11 - 6.02 = 3.98 pounds

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

7 0
3 years ago
Read 2 more answers
What are some expressions that equals 3x-4
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1/2(6x-8) could be one
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3 years ago
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