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oksano4ka [1.4K]
3 years ago
7

2} = \frac{x - 4}{3}" alt="\frac{5}{2} = \frac{x - 4}{3}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
valentina_108 [34]3 years ago
4 0

Step-by-step explanation:

\frac{5}{2}  =  \frac{x - 4}{3}

3 \times \frac{5}{2}  =  \frac{x - 4}{3}

\frac{3}{1}  \times  \frac{5}{2}  =  \frac{x - 4}{3}

cross multiplication

\frac{6 \times 5}{2}  =  \frac{x - 4}{3}

15 =  \frac{x - 4}{3}

15 \times 3 = x - 4

45 + 4 = x

49 = x

harina [27]3 years ago
4 0
23/2 is the correct answer
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1.divide the first term of the numerator by the first team of the denominator, and put that in the answer
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2 years ago
3x + 2y = 7
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It would be the last option, (5, -4)
4 0
2 years ago
5.5 + 2.1x + 3.8x – 4.1
lozanna [386]

Answer:

5.9x + 1.4

Step-by-step explanation:

5.5 + 2.1x + 3.8x - 4.1

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4 0
2 years ago
Read 2 more answers
(-4, -2); y = - 2x + 4
padilas [110]

Answer:

y = -2x - 10

Step-by-step explanation:

Slope intercept form of equation is of form

y = mx+c

where m is the slope of line and c is the y intercept of the line.

Y intercept is point on y axis where the line intersects the y axis.

_____________________________

Given equation

y = -2x +4

comparing it with y = mx+ c

m = -2 , c = 4

_____________________________

when two lines are parallel, their slopes are equal.

Let the equation of new line in slope intercept form be y = mx + c

Thus slope of of new required line is -2

Thus m for new line is -2.

now, equation of required line : y = -2x+c

Given that this line passes through (-4, -2). This point shall should satisfy equation  y = -2x+c.

Substituting the value of (-4, -2) we have

-2 = -2(-4)+c

=> -2 = 8 +c

=> -2 -8 = c

=> c = -10.

Thus , equation of required line is  y = -2x - 10.

8 0
3 years ago
I need the answer please help!
fenix001 [56]
Option C is the correct answer as SAS stands for Side, Angle, Side. You would need one side, one angle and another side to be the same for the conditions for congruency to be met.
8 0
1 year ago
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