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3 years ago

Help for my math homework

Mathematics

2 answers:

IRISSAK [1]3 years ago

8 0

Math homework u got to use math plus to get the answers

vichka [17]3 years ago

5 0

The slope is undefined

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2. Multiply 6⁄5 × 25⁄24 .

andrew-mc [135]

6*25=150 and 5*24=120 so now we have a fraction of uh 150/120 :P Then we have to simplify and divide both numbers by 30 so 150 divided by 30 is 5 and 120 divided by 30 is 4. So now we have a fraction of 5/4. If you need it as a mixed number, then im pretty sure the answer is 11/4 :D

5 0

3 years ago

What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract

fgiga [73]

Answer:

$|z| = 27$ -- Modulus

$\theta = \frac{\pi}{3}$ --- Argument

Step-by-step explanation:

Given

$((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Required

Determine the modulus and the argument

We have that:

$z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Expand:

$z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

A complex equation can be expressed as:

$z = |z| e^{i\theta}$

Where

$|z| = modulus$

$\theta = argument$

Where

$e^{i\theta} = (cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})$

So:

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$ becomes

$z = 27(e^{i\frac{\pi}{18}})^6$

By comparison:

$e^{i\theta} = (e^{i\frac{\pi}{18}})^6$

This gives:

${i\theta} = i\frac{\pi}{18}}*6$

${i\theta} = i\frac{6\pi}{18}}$

${i\theta} = i\frac{\pi}{3}}$

Divide through by i

$\theta = \frac{\pi}{3}$

Hence, the modulus, z is:

$|z| = 27$

And the argument $\theta$ is

$\theta = \frac{\pi}{3}$

4 0

3 years ago

Pls help me i think its the first one

iogann1982 [59]

Answer:

the first one

Step-by-step explanation:

6 0

4 years ago

On a piece of paper, graph y>x-1. Then determine which answer choice

zepelin [54]

The graph that matches the given equation is y≥x-1 is Graph A.

Option: C.

<u>Step-by-step explanation:</u>

The given equation y≥x-1 is a linear inequality equation.

Graphing Linear Inequalities differs from graphing regular linear equations. That is it has certain rules to be followed to draw the graph.

First, rearrange the equation as y in the left and other terms in the opposite side.
Check for the line: y= , y≤ and y≥ comes with straight line where as y< and y> comes with a dotted line.
Shading: If y> greater than or y≥ greater than or equal is present then the space above the line has to be shaded. If y< less than or y≤ less than or equal is present then the space below the line has to be shaded.

For the given equation y≥x-1,

The line will be solid passing through (0,-1) and (3,2) since it has y≥. Also, the region above the line is shaded.

So the graph A is the graph that matches the equation y≥x-1.

8 0

3 years ago

How would I graph this 8x-5y=15?

FromTheMoon [43]

This is linear. 8x-5y=15
-5y=15-8x
Divide -5
Y=8/5x-3.
Start at -3 on y axis and go down 8 points and right 3.

8 0

3 years ago

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