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son4ous [18]
2 years ago
10

Which cube root function is always decreasing as x increases?

Mathematics
1 answer:
iragen [17]2 years ago
7 0

Answer: D

Step-by-step explanation:

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Solve for x, given the equation Square root of x plus 9 − 4 = 1.
yuradex [85]
√x + 9 - 4 = 1
     √x + 5 = 1
           √x = -4
           √x = √-4
             x = 2i



3 0
3 years ago
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Find the area of the shaded region 6cm 6cm
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Hope this helps! the answer is option (A). if you still don’t understand after looking at my solution feel free to clarify ya

4 0
3 years ago
Is non-traditional musical notation, like a body percussion composition, considered music?
kykrilka [37]

Answer:

Music is an art form that means individuals can consider what is music to them.

Music in the dictionary describes music as any sound or voice that produces beauty or form. What shapes body percussion in any percussion would be therefore its form or beauty, to be considered music.

If it fails to provide that quality then it is just considered sound or at best notation to music like a short sound can provide would also be notation to music.

5 0
3 years ago
The order for points only matter when naming a ..?
Gnoma [55]

Answer:

Co-ordinate (x, y)

Step-by-step explanation:

5 0
2 years ago
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Triangle ABC is an isosceles triangle in which side
Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using this formula, we get

AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5

BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}

AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5

Now,

Perimeter of triangle ABC = AB + BC + AC

                        =5+\sqrt{10}+5

                        =10+\sqrt{10}

So, perimeter of triangle ABC is 10+\sqrt{10} units.

Therefore, the correct option is B.

4 0
3 years ago
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