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2 years ago

15

I don’t know this need help thank you :)

1 answer:

NNADVOKAT [17]2 years ago

5 0

You should pick number 1 because it more better and people are not going to bug you about oh we are getting pay less

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Mario invested $475 in $45 and $25 stock shares. The number of $25 shares was 5 less than 3 times the number of $45 shares. How

Anit [1.1K]

$\text{Answer : Number of \$45 shares} =120$

$\text{Number of \$25 shares }\\\\= 3\times 120-5\\\\=360-5\\\\=\$355$

Explanation:

Let Number of $45 shares be x

Let number of $ 25 shares be 3x-25

According to question,

$x+3x-5=475\\\\4x-5=475\\\\4x=475+5\\\\4x=480\\\\x=\frac{480}{4}\\\\x=120$

So,

$\text{Number of \$45 shares} =120$

$\text{Number of \$25 shares }\\\\= 3\times 120-5\\\\=360-5\\\\=\$355$

6 0

3 years ago

Read 2 more answers

Please help if you know the answer

dimulka [17.4K]

Answer:

I think that the answer is 10

7 0

2 years ago

Read 2 more answers

Put these numbers from least to greatest. I'm too lazy to do it. it's for trigonometry.

blagie [28]

Answer:

15, 20, 25, 40, 50, 55, 65, 70, 75, 80, 85, 95

Hope this was all the numbers.

:)

8 0

3 years ago

Read 2 more answers

Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy

Margaret [11]

Answer:

Part 1) The exact solutions are

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ and $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

$y=x^{2} +3x$ ----> equation A

$y=2x+5$ ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

<em>Find the exact solutions of the system</em>

equate equation A and equation B

$x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-5=0$

so

$a=1\\b=1\\c=-5$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}$

$x=\frac{-1\pm\sqrt{21}} {2}$

so

The solutions are

$x_1=\frac{-1+\sqrt{21}} {2}$

$x_2=\frac{-1-\sqrt{21}} {2}$

<em>Find the values of y</em>

<em>First solution</em>

For $x_1=\frac{-1+\sqrt{21}} {2}$

$y=2(\frac{-1+\sqrt{21}} {2})+5$

$y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}$

The first solution is the point $(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$

<em>Second solution</em>

For $x_2=\frac{-1-\sqrt{21}} {2}$

$y=2(\frac{-1-\sqrt{21}} {2})+5$

$y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}$

The second solution is the point $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Round to the nearest hundredth

<em>First solution </em>

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ -----> $(1.79,8.58)$

$(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$ -----> $(-2.79,-0.58)$

see the attached figure to better understand the problem

6 0

3 years ago

Write the equation for the graphed function. I worked out y = 5 - 4 (x + 4)^2 but that isn't right. Any help would be appreciate

alexira [117]

Vertex form for a parabola with vertex (p,q) is

$y = a(x-p)^2 + q$

We have (p,q)=(-4,5) and another point (-3,2) so we can solve for <em>a:</em>

$2 = a(-3 - -4)^2 + 5$

$2 = a + 5$

$a = -3$

Putting it together,

Answer: $y = -3(x + 4)^2 + 5$

We could multiply that out if we like but I won't bother.

5 0

3 years ago