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3 years ago

12

Suzanne bought 50 apples at the apple orchard she bought four times as many red apples green apples how many more red apples and

green apples did Suzanne by

1 answer:

Julli [10]3 years ago

7 0

Suzanne has 200 red apples because 50 x 4 = 200. Good luck!

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Find the degree of the polynomial<br><br> 7a3b2 – 2a4 + 4b – 15<br><br> Degree

vesna_86 [32]

When ur polynomial has more then one variable....and this one does...the degree is the highest term degree

7a^3b^2 ....this term has a degree of 5
2a^4...this term has a degree of 4
4b....this term has a degree of 1
15....this term has a degree of 0

so the highest degree term has a degree of 5....so that is the degree of this polynomial.

now if u just had 1 variable, the degree would be the highest exponent

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3 years ago

What is the answer to 2(x+4)-3

gizmo_the_mogwai [7]

2x+8-3
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3 years ago

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The mean yearly rainfall in Sydney, Australia, is about 134 mm and the standard deviation is about 66 mm ("Annual maximums of,"

svetlana [45]

Answer:

At least 202.44 mm in the top 15%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 134, \sigma = 66$

How many yearly mm of rainfall would there be in the top 15%?

At least X mm.

X is the 100-15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037.

$Z = \frac{X - \mu}{\sigma}$

$1.037 = \frac{X - 134}{66}$

$X - 134 = 66*1.037$

$X = 202.44$

At least 202.44 mm in the top 15%.

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3 years ago

1. Type mmnn using exponents.

kompoz [17]

Step-by-step explanation:

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$\bold{6.}\\\\3x^2\ for\ x=6\ /\text{put x = 6 to the expression}/\\\\3(6)^2=3(36)=108\\\\\bold{7.}\\\\3y^2+2y\ for\ y=3\ /\text{put y = 3 to the expression}/\\\\3(3)^2+2(3)=3(9)+6=27+6=33$

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3 years ago

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ira [324]

Answer:

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Step-by-step explanation:

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