This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3
Second part: when (6x + 2) is negative.
-(6x + 2) < 10 Divide both sides of inequality by -1 and change the sign.
(6x + 2) > -10
6x + 2 > -10
6x > -10 - 2
6x > -12 Divide both sides by 6.
x > -12/6
x > -2.
Combined solution: x < 4/3 and x > -2
-2 < x < 4/3.
Graph is a line on the number line between -2 and 4/3.
-2 and 4/3 are excluded from solution.
Answer:
The answer to your question is letter B
Step-by-step explanation:
Process
1.- Find two points of each line
Line A (-2, 0) (-1, 2)
Line B (-1. - 5) (-6, 0)
2.- Find the slope and equation of each line
Line A


m = 2
y - 0 = 2(x + 2)
y = 2x + 4
Line B


m = -1
y - 0 = -1(x + 6)
y = -x - 6
3.- Find the inequalities
Line A, we are interesteed in the lower area of the line, so the inequality is
y ≤ 2x + 4
Line B, we are also interested in the lower area of the line so the inequality is
y ≥ - x - 6
Answer:

and

Step-by-step explanation:
First make all the fractions into improper fractions

After doing that put them back into the problems
Problem 1)
÷
, plug in the improper fractions
÷
to divide, you need to flip the second fraction and multiply
·
=
then reduce

Problem 2)
÷
Plug in improper fraction
÷
Then flip second fraction and multiply
·
Multiply
Reduce, or make it a mixed number

Answer:
always true
Step-by-step explanation:
Given
2(x + 3) = 5x + 6 - 3x ← distribute left side
2x + 6 = 2x + 6
Since both sides are equal then any real value of x is a solution.
Thus the equation is always true
Answer:
5.19
Step-by-step explanation: