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3 years ago

Write the number in scientific notation.

Mathematics

1 answer:

mylen [45]3 years ago

7 0

Pretty sure it’s C. You need to make the 4 an exponent tho.

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Pearson bought a 2012 Chevy Malibu for $16,800. It depreciates by 5% per year. How much will Pearson's Chevy be worth after 15 y

pickupchik [31]

Answer:

the worth after 15 years is $7,783.29

Step-by-step explanation:

Given that

The purchase price is $16,800

It would be depreciated 5% per year

We need to find out the worth after 15 years

= $16,800 × (1 - 0.05)^15

= $16,800 × 0.46329123

= $7,783.29

Hence, the worth after 15 years is $7,783.29

In this way it should be determined

3 0

3 years ago

If there are 26 successes in a sample with a size of 40what is the sample

IRISSAK [1]

El gobierno de la comunidad autónoma del gobierno ha decidido en un plazo

5 0

3 years ago

A new solid is created by cutting a right rectangular prism from a cube. The right rectangular prism has a length

Mila [183]

Volume of solid created = $85m^{3}$ .

<u>Step-by-step explanation:</u>

We have , A new solid is created by cutting a right rectangular prism from a cube. The right rectangular prism has a length of 5 m, a width of 4 m, and a height of 2 m. The side lengths of the cube are 5 m . Volume of solid created = Volume of cube - Volume of rectangular prism

Volume of cube = $side^{3}$

⇒ $Volume1 = side^{3}$

⇒ $Volume1 = 5^{3}$

⇒ $Volume1 = 125m^{3}$

Volume of rectangular prism = $wlh$

⇒ $Volume2 = wlh$

⇒ $Volume2 = 5(4)(2)$

⇒ $Volume2 = 40m^{3}$

Now, Volume of solid created = Volume of cube - Volume of rectangular prism

⇒ Volume of solid created = $Volume1 - Volume2$

⇒ Volume of solid created = $125m^{3} - 40m^{3}$

⇒ Volume of solid created = $85m^{3}$

∴ Volume of solid created = $85m^{3}$ .

8 0

3 years ago

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

3 years ago

Please help with this question on percentages.

wel

Answer:

£65.40

Step-by-step explanation:

4 0

2 years ago