4 years ago

A restaurant has 6 pizza toppings to choose from. How many diffrent 3 topping pizzas are possible

1 answer:

8 0

$\bf _nC_r=\cfrac{n!}{r!(n-r)!}\qquad 
\begin{cases}
n=6\\
r=3
\end{cases}\implies _6C_3=\cfrac{6!}{3!(6-3)!}$

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