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lesya [120]
3 years ago
9

Answer the question on the picture!

Mathematics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

64 square inches

Step-by-step explanation:

im not 100% sure but i think its right

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Find the volume for the cone
Zanzabum

Answer:

1526.81 mi cubed

Step-by-step explanation:

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In the first four months of the year, Noralie's jewelry sales were declining. After April, her sales began to improve. The function below represents her monthly sales. Which graph represents the Noralie's sales?

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Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8
goblinko [34]
\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y  = \frac{17}{14} } \atop {x+7y=8}} \right.

To solve this system by substitution, first isolate x in the second equation.

x+7y=8
x+7y-7y=8-7y
x=8-7y

Now, plug this expression (8-7y) for x in the top equation to solve for y.

\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}
3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}
72-63y+8y=17
72-55y=17
-55y=17-72
-55y=-55
y=1

Now that you have y, plug it into the second equation and solve for x.

x+7y=8
x+7(1)=8
x+7=8
x=1

Last step is to plug your x- and y-values in to both equations to check your work.

\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}

\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ;  \frac{1}{3} * \frac{8}{8} = \frac{8}{24}

\frac{9}{24} + \frac{8}{24} = \frac{17}{24}  <--True

1+7(1)=8
1+7=8   <--True

Answer:
x=1 \\ y=1
5 0
4 years ago
Find the distance between 4 2/3 and −5 1/3
svetoff [14.1K]

Answer:

The distance between these two is 10.

Step-by-step explanation:

In order to find this, we simply need to subtract the values from one another. If the value is then negative, we take the absolute value to find the distance.

4 2/3 - -5 1/3

4 2/3 + 5 1/3

10

8 0
3 years ago
FIND THE DISTANCE BETWEEN THE POINTS. ROUND THE ANSWER TO TWO DECIMAL POINTS (3,2) (8,2)
defon

Answer:5

Step-by-step explanation:

If you are looking for the distance then start counting on the first decimal and stop at the second

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3 years ago
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