FIND THE DISTANCE BETWEEN THE POINTS. ROUND THE ANSWER TO TWO DECIMAL POINTS (3,2) (8,2)

Mathematics

1 answer:

defon3 years ago

5 0

Answer:5

Step-by-step explanation:

If you are looking for the distance then start counting on the first decimal and stop at the second

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A recipe for 24 cookies calls for 4 tablespoons of sugar. If you make 40 cookies and use 5 tablespoons, will the cookies taste t

uranmaximum [27]

Answer:

Step-by-step explanation:

No, because they wouldn't contain the same amount of sugar per cookie

for the first recipe - 24 cookies with 6 tablespoons

thats 6/24 so 0.25 tablespoons of sugar per cookie

for the second recipe - 36 cookies with 10 tablespoons

thats 10/36 so 0.276 tablespoons per cookie

the cookies in the second recipe would be slightly sweeter than the cookies in the first

5 0

3 years ago

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Aloiza [94]

Answer:

The answer is B. inches....

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3 years ago

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Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$