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Bezzdna [24]
2 years ago
12

Sean and his chartered a fishing boat for the day Sean caught a blue marlin and an amberjack. The weight of the blue marlin way

12 times as great of the amberjack. The combined weight of both fish was 273 pounds. How much did each fish weight
Mathematics
1 answer:
Serjik [45]2 years ago
4 0

Answer:

The weight of the blue marlin = b = 252 pounds

The weight of the amber jack = a = 12 pounds

Step-by-step explanation:

Sean and his chartered a fishing boat for the day Sean caught a blue marlin and an amberjack.

Let

The weight of the blue marlin = b

The weight of the amber jack = a

The weight of the blue marlin weigh 12 times as that of the amberjack.

b= 12a

The combined weight of both fish was 273 pounds.

= a + b = 273 pounds

b = 12a

Hence

a + 12a = 273 pounds

13a = 273 pounds

a = 273 pounds/13

a = 21 pounds

b = 12a

b = 12 × 21 pounds

= 252 pounds

Hence:

The weight of the blue marlin = b = 252 pounds

The weight of the amber jack = a = 12 pounds

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6j + 1/3n = 134...multiply by 3....18j + n = 402
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the multiplying by 3 is optional...I just did it because it is easier to work with equations when there are no fractions.

18j + n = 402....multiply by -3
j + 3n = 93
----------------
-54j - 3n = - 1206 (result of multiplying by -3)
j + 3n = 93
----------------add
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j = -1113/-53
j = 21

j + 3n = 93
21 + 3n = 93
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3n = 72
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