Find a formula for an arithmetic sequence that begins 80, 83, 86, 89, ...
1 answer:
You might be interested in
{x,y} = {-2,3}
[1] 2x + 4y = 8
[2] x - 3y = -11
4y + 2x = 8
-3y + x = -11
Solve equation for the variable x
[2] x = 3y - 11
Plug this in for variable x in equation [1]
[1] 2•(3y-11) + 4y = 8
[1] 10y = 30
Solve equation [1] for the variable y
[1] 10y = 30
[1] y = 3
By now we know this much :
x = 3y-11
y = 3
Use the y value to solve for x
x = 3(3)-11 = -2
Solution :
{x,y} = {-2,3}
<h2 />~Savannah
Answer:
b
Step-by-step explanation:
if a is perp to b, and b is parallel to c, and c is parallel to d, then a is perp to d
