Find a formula for an arithmetic sequence that begins 80, 83, 86, 89, ...
1 answer:
Answer:
= 3n + 77
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 80 and d = a₂ - a₁ = 83 - 80 = 3 , then
= 80 + 3(n - 1) = 80 + 3n - 3 = 3n + 77
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