Question

Find a formula for an arithmetic sequence that begins 80, 83, 86, 89, ...​

Answer 1

Answer:

$a_{n}$ = 3n + 77

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 80 and d = a₂ - a₁ = 83 - 80 = 3 , then

$a_{n}$ = 80 + 3(n - 1) = 80 + 3n - 3 = 3n + 77