3 years ago

Find a formula for an arithmetic sequence that begins 80, 83, 86, 89, ...

Mathematics

1 answer:

mel-nik [20]3 years ago

3 0

Answer:

$a_{n}$ = 3n + 77

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 80 and d = a₂ - a₁ = 83 - 80 = 3 , then

$a_{n}$ = 80 + 3(n - 1) = 80 + 3n - 3 = 3n + 77

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0^9 +7x+189yx−3y

+7x−3y

+7x+3y

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−7x+3y

+7x+189yx−3y

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{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y

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Find a formula for an arithmetic sequence that begins 80, 83, 86, 89, ...​

Find a formula for an arithmetic sequence that begins 80, 83, 86, 89, ...