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2 years ago

10

Audria rode her bicycle for 2 hours. She drove a total of 21 miles. At this rate, how many miles will she bike in ½ hour? A 612

6 1 2 B 634 6 3 4 C 534 5 3 4 D 514

1 answer:

just olya [345]2 years ago

7 0

Answer:

5 1/4

Step-by-step explanation:

Speed = distance / time

21 / 2 = 10.5

10.5 = distance / 0.5

distance = 10.5 x 0.5 = 5,25 miles or 5 1/4

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A right rectangular prism is 5 1/4 in. wide, 12 1 2 in. long, and 4 in. tall.

lozanna [386]

Answer: $V = 262\frac{1}{2}$ $cm^{3}$

Step-by-step explanation:

$V = LWH$

$V = 5\frac{1}{4}$ X $12\frac{1}{2}$ X 4

$V = \frac{21}{4}$ X $\frac{25}{2}$ X $\frac{4}{1}$

$V = \frac{525}{2}$

$V = 262\frac{1}{2}$ $cm^{3}$

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3 years ago

Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

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Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>

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Step-by-step explanation:

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