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Free_Kalibri [48]
3 years ago
14

Write the equation of the line in fully simplified slope-intercept form.

Mathematics
1 answer:
sesenic [268]3 years ago
6 0

Answer: y = -x - 8

Step-by-step explanation:

y = -x - 8

slope = -1/1

yint = -8

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130/105 in its simplest form
Andreas93 [3]
130/105 in its simplest form

\dfrac{130}{105}= \qquad 130= 2.5.13\qquad 105=3.5.7 \\  \\  \\  \dfrac{130}{105}=  \dfrac{2.5.13}{3.5.7} \\  \\  \\   \dfrac{130}{105}=  \dfrac{2.\not 5.13}{3.\not 5.7}=  \dfrac{2.13}{3.7}=  \boxed{ \dfrac{26}{21}} \\  \\  \\ \boxed{ \dfrac{130}{105}=  \dfrac{26}{21}}

I wish you much success in your studies!!!!
5 0
4 years ago
Point G is on line segment FH. Given FG=5x+2,GH=3x-1, and FG=9, determine the numerical length of FG
stealth61 [152]

Given:

FG=5x+2

GH=3x-1

FG=9

Let us draw the line segment as follows,

Equating the length of FG, we get,

\begin{gathered} 5x+2=9 \\ 5x=9-2 \\ 5x=7 \\ x=\frac{7}{5} \end{gathered}

Substitute the value of x in the given value of GH,

\begin{gathered} GH=3x-1 \\ =3(\frac{7}{5})-1 \\ =\frac{21}{5}-1 \\ =\frac{16}{5} \\ =3.2 \end{gathered}

And the total length FH is,

\begin{gathered} FH=FG+GH \\ =9+3.2 \\ =12.2 \end{gathered}

Hence, the lengths are,

\begin{gathered} FG=9 \\ GH=3.2 \\ FH=12.2 \end{gathered}

8 0
1 year ago
What is 802.6 in expanded form
ankoles [38]

Answer:

802+6 tenths.

Step-by-step explanation:

802 is not apart of the decimal. (I might sound stupid but I dont remember expanded form as much.) Only the 6 is apart of the decimal itself. 802 is just numbers. The 6 is pretty much the decimal.

4 0
4 years ago
Algebra 2, I need help!!! Solve x^2 + 6x + 7 = 0. If you are going to comment in here please know the answer, this is so serious
docker41 [41]

Answer:

Third option

Step-by-step explanation:

We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:

x = (-3 ± √(3² - 1 * 7)) / 1 = -3 ± √2

6 0
3 years ago
What is the leading coefficient of this polynomial when written in standard form?<br><br> 1-2x+5x^4
Goshia [24]

Answer:

5!!

Step-by-step explanation:

When writing the polynomial in standard form, we have:

5X⁴ - 2X + 1

The leading coefficient is 5, since it's part of the term with the highest degree.

6 0
3 years ago
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