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PIT_PIT [208]
3 years ago
5

HELP ME WITH THIS PLEASE

Mathematics
1 answer:
nadezda [96]3 years ago
7 0

question number 36 the answer is always true because rational numbers are numbers that can be turned into fractions or simple fractions easily and any integers that is positive added together will provide a positive answer.

37. the answer is always true because and a negative integer and a negative integer added together will give a negative answer.

38. sometimes true. a positive intergee plus a negative interger can give a positive or negative answer. eg -3+2=-1 but -4+8=4

39. always true. + multiply + =+

40. never true. - multiply - = +

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Can somebody help me with this problem
soldier1979 [14.2K]
115 degrees because there are 180 degrees in a triangle so let the missing angle in the trinagle be x. Then we have x+75+40=180. Solving for x and subtracting that from 180 (supplementary angles) we get 115 degrees.
4 0
3 years ago
Help with this question, please!!
IceJOKER [234]

Answer:

  72°

Step-by-step explanation:

You correctly found x, but the measure of the angle is ...

  4x-22 = 4·23.5-22 = 72°

___

or (6x-69)° = (141-69)° = 72°

4 0
3 years ago
How do you find the missing height of a triangle?
g100num [7]

Answer:

Use the Pythagorean theorem

Step-by-step explanation:

The pythagorean theorem is a^{2} +b^{2} =c^{2} where a is a height, b is a height, and c is the hypotenuse, which is the longest side of a triangle. For example, if the triangle has two side with lengths of three and four we would put them into the equation to get:

3^{2} +4^{2} =c^{2}

Simplify the equation to get:

9+16=c^2

Add 16 and 9 to get 25 and take the square root of both sides:

\sqrt{25} =c

The sqrt of 25 is 5. Therefore, the length of the hypotenuse, or c, is 5.

8 0
3 years ago
Read 2 more answers
Which of the equations below could be the equation of this parabola?
nirvana33 [79]

Answer:

 y=-4x^2  is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

y=-4x^2

\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)

As

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)

\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}

y=-4x^2

\mathrm{The\:parabola\:params\:are:}

a=-4,\:m=0,\:n=0

x_v=\frac{m+n}{2}

x_v=\frac{0+0}{2}

x_v=0

\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=-4\cdot \:0^2

y_v=0

Therefore, the parabola vertex is

\left(0,\:0\right)

\mathrm{If}\:a

\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}

a=-4

\mathrm{Maximum}\space\left(0,\:0\right)

so,

\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)

Therefore,  y=-4x^2  is the equation of this parabola. The graph is also attached.

7 0
3 years ago
What’s the answer to this?
Elina [12.6K]

Step-by-step explanation:

Line is passing through the points:

(-2,\:3)=(x_1,\:y_1) \:\&\: (2,\:5)=(x_2 ,\:y_2)

Equation of line in two point form is given as:

\frac{y -y_1 }{y_1 -y_2 } = \frac{x -x_1 }{x_1 -x_2 } \\ \\ \therefore \frac{y -3}{ 3 -5} = \frac{x -(-2) }{-2 -2} \\ \\ \therefore \frac{y -3}{ - 2} = \frac{x -(-2) }{-4} \\ \\ \therefore \frac{y - 3}{1} = \frac{x +2}{2} \\ \\ \therefore \: y-3= \frac{x}{2} + \frac{2}{2} \\ \\\therefore \: y= \frac{x}{2} + 1 +3\\ \\ \huge \red{ \boxed{\therefore \: y= \frac{1}{2} \:x+ 4}}\\ is \: the \: required \: equation \: of \: line.

4 0
3 years ago
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