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olga nikolaevna [1]
3 years ago
10

Select the correct answer.

Mathematics
2 answers:
bezimeni [28]3 years ago
4 0

Answer:

4

Step-by-step explanation:

PLATO correct answer

fredd [130]3 years ago
3 0

Stocks = 250

Net income = $4,000,000

Outstanding Shares = $1,000,000

Earnings Per Share = ?

Formula: EPS = Net Income / Outstanding Shares

Solution: EPS = Net Income / Outstanding Shares

= $4,000,000 / $1,000,000

= 4

Answer: Earnings Per Share = 4

You might be interested in
1. Oblicz:
dem82 [27]

Step-by-step explanation:

1. Oblicz:

a) Liczbę o 15% mniejszą od 60

b) Liczbę, której 15% stanowi 60

c) Jakim procentem 60 jest 15

d) O ile %większa jest 60 od 15

2. Kasia kupiła buty na wyprzedaży przecenione o 20%. Ich cena początkowa to 180 zł. W domu sprzedała je siostrze zarabiając na tym 10% wartości. Ile zapłaciła Kasi siostra za buty?

3. Liczba, którą powiększymy o 20% daje nam 30. Jaka to była liczba?

4. Za dwie książki zapłacono 42 zł. Ile kosztuje droższa z nich, jeżeli jedna jest o 25 % tańsza od drugiej?

5 0
3 years ago
If 800g of a radioactive substance are present initially and 8 years later only 450g remain, how much of the substance will be p
artcher [175]

A=Pe^(rt)

P = 800g

t = 8 years

A = 450g

r = This is what we will try and find to start with

450=800e^(r*8)

After running the math through a calculator, we end with r = -0.07192

Now we just re-input this information into our equation: A=800e^(-0.07192*16)

A=800e^(1.15072)

Now we will re-write the equation using the negative exponent rule:

A = 800 1/e^1.15072

Combine right side:

A = 800/e^1.15072

Then do the math:

A = 253.12709836......

That will give us A = 253 (rounded to the whole number)

I hope this helps! :)

5 0
3 years ago
Is 14.5℅ equivalent to 14.5
vova2212 [387]
No, it actually is not!

If you are to change it to a number, 

14.5% = .145
7 0
3 years ago
Read 2 more answers
Which expression is equivalent to (2x²y) ³?<br> O 2x¹y4<br> 2x¹2y3<br> 8x¹ y<br> O 8x¹2y³
natta225 [31]

Answer: 8x^6 y^3

Step-by-step explanation:

See attached image.

7 0
2 years ago
A recent survey based on a random sample of n=470 voters, predicted that independent candidate for the mayoral election will get
julsineya [31]

I have an expression

\sigma = \sqrt{p(1-p)/n}

floating around in my head; let's see if it makes sense.

The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

E( (b-p)^2 ) =  (-p)^2(1-p) + (1-p)^2p = p(1-p)

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

\sigma = \sqrt{p(1-p)/n}

Plugging in the numbers,

\sigma = \sqrt{.24(1-.24)/490} = 0.019 = 1.9\%

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.

So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.

7 0
4 years ago
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