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loris [4]
3 years ago
12

What's 2 + 2 in a mathematical sense

Mathematics
1 answer:
Setler [38]3 years ago
4 0

In a mathematical sense..

Not to make it too complicated, however, here's where we get on to the real mathematics.

There are infinite equations for 2 + 2. The gap between any number can be infinite if you keep giving it more numerical content. However, solving 2 + 2 can be very tricky.

1 + 1 + 1 + 1 = 4. Easy, right? Wrong. We can deduct from this equation that 1 + 1 = 2, so if we do 1 + 1 PLUS 1 + 1, (1 + 1 + 1 + 1 again), that equals four, because 1 + 1 is 2 and if we add another 1 to 2, 1 + 2, it equals 3, so 1 + 3 = 4. I'd like to remind you-- this works both ways, whether or not it's 3 + 1 or 1 + 3, it equals 4. If we carry the 1 from the three and put it in a separate number in an equation, said equation is now 1 + 1 + 2. It still equals 4, because 1 + 1 = 2 and if you take 2 and put it in 1 + 1's place, it's 2 + 2.

2 + 2 = 4.

(this was a joke answer, don't take anything said in this answer seriously.. OR you can if you want, because it's all true.. 2 + 2 = 4.)

Hope this helped!

- William.

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If I were to start with $50 and add $20 each week for 12 weeks, what is an equation that represents the relationship between the
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This is a function y = mx + b:

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3 years ago
Which expression is equivalent to 4√24x∧6y÷ 128x∧4y∧5
LenKa [72]

Answer:

Option D.  \sqrt[4]{\frac{3x^{2}}{2y}}

Step-by-step explanation:

\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}}

\sqrt[4]{(\frac{24}{128})\times (\frac{x^{6}}{x^{4}})\times (\frac{y}{y^{5}})}

= \sqrt[4]{(\frac{3}{16})\times {(x)^{6-4}}\times{(y)^{1-5}}}

= \sqrt[4]{(\frac{3}{16})\times x^{2}y^{-4}}

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= \sqrt[4]{(3\times x^{2)\times (\frac{y^{-1}}{2})^{4}}}

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Option D. \sqrt[4]{\frac{3x^{2}}{2y}}  is the correct answer.

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