Question

The vertices of a triangle are located at the points A(0, 1), B(2, 4) and C(3, 0). The triangle is translated 5 units down to obtain triangle A′B′C′. What are the coordinates of the vertices of triangle A′B′C

Answer 1

Answer:

The coordinates of the vertices of triangle A'B'C' are $A'(x,y) = (0,-4)$, $B'(x,y) = (2,-1)$ and $C'(x,y) = (3,-5)$.

Step-by-step explanation:

According to this statement, triangle ABC must be translated 5 units in the -y direction to form triangle A'B'C'. We need to use the following operations:

$A'(x,y) = A(x,y) +(0,-5)$ (1)

$B'(x,y) = B(x,y) +(0,-5)$ (2)

$C'(x,y) = C(x,y) + (0,-5)$ (3)

If we know that $A(x,y) = (0,1)$, $B(x,y) = (2,4)$ and $C(x,y) = (3,0)$, then the new  vertices of the rectangle are, respectively:

$A'(x,y) = (0,-4)$, $B'(x,y) = (2,-1)$, $C'(x,y) = (3,-5)$