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Snowcat [4.5K]
3 years ago
14

Solve the simultaneous equations 6x + 5y = 32 2x + 5y = 12 V = y =

Mathematics
1 answer:
Anni [7]3 years ago
8 0

Answer: x = 5, y = 2/5

Step-by-step explanation:

We have the system of equations:

6*x + 5*y = 32

2*x + 5*y = 12

To solve it, we can start by isolating one of the variables in one of the equations.

Because in both of them we have the term 5*y, i will isolate 5*y in the second equation:

5*y = 12 - 2*x

Now let's replace it in the first equation:

6*x + (12 - 2*x) = 32

Now let's solve it for x

6*x + 12 - 2*x = 32

(6*x - 2*x) = 32 - 12 = 20

4*x = 20

x = 20/4 = 5

Now we know the value of x, we can replace it in the equation:

5*y = 12 - 2*x

to find the value of y.

5*y = 12 - 2*5

5*y = 2

y = 2/5

Then the solution of the system is x = 5, y = 2/5

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what is a correct first step in solving the inequality –4(3 – 5x)≥ –6x 9? –12 – 20x ≤ –6x 9 –12 – 20x ≥ –6x 9 –12 20x ≤ –6x 9 –1
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Find the equation of the line with a slope of 1/5 that passes through the point (10,9).
IRINA_888 [86]

Answer:

The equation of the line with a slope of 1/5 that passes through the point (10,9) is:

  • y=\frac{1}{5}x+7

Step-by-step explanation:

Given

Slope = m = 1/5

Point (10, 9)

To Determine

An equation of the line with a slope of 1/5 that passes through the point (10,9).

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

substituting the values m = 1/5 and the point (10, 9) in the equation

y-y_1=m\left(x-x_1\right)

y-9=\frac{1}{5}\left(x-10\right)

Add 9 to both sides

y-9+9=\frac{1}{5}\left(x-10\right)+9

y=\frac{1}{5}x-2+9

y=\frac{1}{5}x+7

Therefore, the equation of the line with a slope of 1/5 that passes through the point (10,9) is:

  • y=\frac{1}{5}x+7
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