QUESTION 1
The figure is a tra-pezoid.
The area of a trapezoid is given by the formula;

We substitute the values to obtain;



QUESTION 2
The approximate length of the ribbon is equal to the circumference of the circular table cloth.
We can find this by using the formula for calculating the circumference of a circle.

where
is the radius of the circular table cloth.
We substitute this value and
into the formula to get;


The approximate length of the ribbon is 22.0ft to the nearest tenth.
QUESTION 3
Type of quadrilateral:Rectangle
Explanation: A rectangle has 4 angles that are right angles.
The two pairs of opposite sides of a rectangle are also congruent.
QUESTION 4.
The circumference of a semi circle is calculated using the formula;
where
is the radius of the semicircle.
QUESTION 5
The area of the entire figure is the area of the semicircle plus the area of the isosceles triangle.





QUESTION 6
The area of the parallelogram is given by the formula;

From the diagram,
.
Given, A=23.7 inches squared.
We substitute the values to obtain;



QUESTION 7
The area of a rectangle is given by the formula;

The area of the bigger rectangle 
The area of the smaller rectangle 
The area of the shaded region 