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mote1985 [20]
3 years ago
13

In the right triangle shown, m of angle N = 30 degrees and MO = 8. How long is NO?

Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

Step-by-step explanation: 16

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80*0.25=20
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Solve7+x/4=5 For x please show steps
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paul is born on his grandfather 60th birthday. In how many years will is Grandfather be 11 times as old as Paul?
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HELP ASAP PLEASE ILL GIVE BRAINIEST!!! <br> I’m stuck !!!!
rosijanka [135]

Answer:

Therefore the value of EC is 13 unit.

Step-by-step explanation:

Given:

ABCD is a Rectangle

EC = 6x + 1

AE = x +11

To Find:

EC = ?

Solution:

ABCD is a Rectangle .........Given

Diagonal of Rectangle Bisect each other. .......Property of Rectangle

AE = EC

Substituting the values we get'

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7 0
3 years ago
Consider a drug testing company that provides a test for marijuana usage. Among 310 tested​ subjects, results from 28 subjects w
Naily [24]

Answer:

z=\frac{0.0903 -0.1}{\sqrt{\frac{0.1(1-0.1)}{310}}}=-0.569  

The p value for this case can be calculated with this probability:

p_v =P(z  

Since the p value is higher than significance level we don't have enough evidence to conclude that the true proportion is significantly less than 0.1

Step-by-step explanation:

Information given

n=310 represent th sample selected

X=28 represent the subjects wrong

\hat p=\frac{28}{310}=0.0903 estimated proportion of subjects wrong

p_o=0.1 is the value to verify

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

System of hypothesis

We want to test the claim that less than 10 percent of the test results are wrong ,and the hypothesis are:  

Null hypothesis:p\geq 0.1  

Alternative hypothesis:p < 0.1  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.0903 -0.1}{\sqrt{\frac{0.1(1-0.1)}{310}}}=-0.569  

The p value for this case can be calculated with this probability:

p_v =P(z  

Since the p value is higher than significance level we don't have enough evidence to conclude that the true proportion is significantly less than 0.1

5 0
3 years ago
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