first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.
let's notice the vertex, or U-turn, is at (-2, 2)
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cboxed%7By%3Da%28x-%20h%29%5E2%2B%20k%7D%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B-2%7D%7B%20h%7D%2C%5Cstackrel%7B2%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5C%5C%20y%3D%2B1%5Bx-%28-2%29%5D%5E2%2B2%5Cimplies%20y%3D%28x%2B2%29%5E2%2B2%20)
A^3-19 should be the answer, good luck
Answer:
The phone could be either 24 feet away from them or 70 feet away from them because the person that lost the phone could be on the other side of the cell phone tower
Step-by-step explanation:
you are going to need to find the common name of common denominator 4/1 over 4 plus 1 over 6 equal to look for the commentator of 15 and 6 what goes into 15 and 6 is going to 15 and 6 the common denominator will be actually 12 to 6 only go into 15 2 times cuz I can't get close to 15 than q2 so you have to common denominator now this is going to be both 1/12 + 1/12 is going to be either 2/24 or 2/12
The full range is

(length

), so the half range is

. The half range sine series would then be given by

where

Essentially, this is the same as finding the Fourier series for the function

Integrating by parts yields

So the half range sine series for this function is simply