Line because a line is not 3-D
1) last number times 4 and subtract 1
2) last number times2 and add 2
3) you figure out
The two equations would yield no solution if they are dependent. That means that both equations are equivalent. You can determine this by manipulating the equations through simplification. For example, a dependent equation would be:
3x - 4y = 2
3x/2 - 2y = 1
Another dependent equation is when you multiply the whole equation with a number, say 3.
(3x - 4y = 2)3
9x - 12y = 6
Answer:
m∠XYZ=106°, m∠XWY = 53°
Step-by-step explanation:
XYZ is a central angle, its arc is XY = 106°. so m∠XYZ = mXY=106°
XWY is an inscribed angle, its arc XY = 106°, so m∠XWY =1/2 mXY=1/2*106=
= 53°
we have that

we know that
Triangles ABC and A'B'C' are similar
Step 
Find the distance AB and distance A'B' with the formula

a) distance AB



b) distance A'B'




Step 
Find the scale factor

therefore
the answer is
the scale factor of the dilation is equal to 