Answer:
The expression that is equivalent is 2 RootIndex 3 StartRoot 3 EndRoot
:
![2\sqrt[3]{3}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
Hi
As we have 24 Superscript one-third, this is
.
, therefore
, so
.
Answer:
it wants you to factor/solve for 36a^4 b^10 -81a^18 B^20 using those strategies, so i believe you're already done.
Step-by-step explanation:
IM NOT A EXPERT THOUGH
This can be calculated using the formula:
P = L((r/n)*(1 + r/n)^(n*t))/((1 + r/n)^(n*t) - 1)
Where:
L = 4759
r = 0.209
n = 12
t = 3
So plugging in our data:P = 4759((0.209/12)*(1 + 0.209/12)^(12*3))/((1 + 0.209/12)^(12*3) - 1)
Which will give us the amount of: $179.05 is the monthly repayments.
Other info:
Total interest:$1,686.80
Total cost:$6,445.80
<em>2 solutions</em>
<em>X= 16</em>
<em>X=49</em>
Step-by-step explanation:
<em>original equation</em>
<em>x-11√x+28 = 0</em>
<em> Isolate</em>
<em> -11√x = -x-28+0</em>
<em> Tidy up</em>
<em> 11√x = x+28</em>
<em> Raise both sides to the second power</em>
<em> (11√x)2 = (x+28)2</em>
<em>After squaring</em>
<em> 121x = x2+56x+784</em>
<em> Plug in 49 for x </em>
<em> 11√(49) = (49)+28</em>
<em>Simplify</em>
<em> 11√49 = 77</em>
<em> Solution checks !!</em>
<em> Solution is:</em>
x = 49
<em>Plug in 16 for x </em>
<em> 11√(16) = (16)+28</em>
<em>Simplify</em>
<em> 11√16 = 44</em>
<em> Solution checks !!</em>
<em> Solution is:</em>
x = 16
2.5 years = 30 months
7500$ in 30 months
x$ in 1 month
___________________
x = (7500*1)/30 = 250
The answer is 250$/month.