Answer:
118
Step-by-step explanation:
10-4xy
10-4(9)(-3)
10-36(-3)
10+108
118
Answer:
step 1
Find the average growth per year of the populations of rabbits farm A
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=40
average=[40-5]/2---------> 17.5
step 2
Find the average growth per year of the populations of rabbits farm B
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=30
average=[30-5]/2---------> 12.5
step 3
Compare the average growth per year of the populations of rabbits on both farms
farm A=17.5
farm B=12.5
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.
therefore
the answer is the option C)
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.
Step-by-step explanation:
Answer:
738
Step-by-step explanation:
984 ÷ 100 = 9.84
9.84 × 75 = 738
75/100
Answer:
is 200 times larger than 
Step-by-step explanation:
To compare both values we divide the exponents
6 divide by 3 is 2
for simplify exponents we use exponential property
a^m / a^n = a^(m-n)
is 200 times larger than
Number 1 is 14/10 number 4 is 3 1/7 number 5 is 3 5/6
