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WITCHER [35]
2 years ago
11

There are 1,023 M&M's in a bag. Out of 1,023 M&M's, 132 M&M's are blue, 69 are green, 68 are brown, 63 are olive, 62

are teal, 60 are navy, 56 are black, 55 are red, 54 are orange, 50 are yellow, 45 are lime, 45 are cyan, 44 are purple, 42 are magenta, 40 are gray, 40 are pink, 31 are apricot, 29 are beige, 24 are mint, and 14 are lavender. What is the probability that you pull 1 blue M&M in [...] amount of days, given that you are only allowed to pull 5 random M&M's per day, and there is no guarantee that you will pull 1 random M&M per day, assuming that you typically pull 1 to 3 random M&M's per day? Also, calculate the same probability if you pull 5 random M&M's per day.
Mathematics
1 answer:
lesantik [10]2 years ago
4 0

The probability that the person pulls 1 blue M&M given that one is only allowed to pull 5 random M&M's per day will be 0.6450.

<h3>How to calculate probability?</h3>

From the information given, there are 1,023 M&M's in a bag and out of 1,023 M&M's, 132 M&M's are blue.

Therefore, the probability of getting a blue M&M will be:

= 132/1023

= 0.1290

Therefore, since the person is given the chance to pull 5 random M&M's per day, the probability will be:

= 0.1290 × 5

= 0.6450

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

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Simplify the square root of 32/5
elixir [45]
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and
\sqrt{ab^2} =b \sqrt{a}
\sqrt{ \frac{32}{5} } = \frac{ \sqrt{(4^2)(2)} }{ \sqrt{5} } = \frac{ 4\sqrt{2} }{ \sqrt{5} }
times whoe thing by \frac{ \sqrt{5} }{ \sqrt{5} }
\frac{4 \sqrt{10} }{5}


3 0
3 years ago
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
2 years ago
At the local pet store, zebra fish cost $2.10 each and neon tetras cost $1.85 each. If
nignag [31]
The answer is a)

Let me know if you need an explanation
7 0
3 years ago
A mountain bike originally priced at $960.00 is up for sale at a discount of 14%. What is the price of the mountain bike after t
PilotLPTM [1.2K]

Answer:

$825.60

Step-by-step explanation:

Since the price of it is $960.00, it means that it's 100%.

100% = 960

1% = 960 ÷ 100 = 9.6

14% = 9.6 x 14 = 134.40

Since they asked for after the discount, deduct the price of the discount with the original price.

Mountain bike after 14% discount =

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7 0
3 years ago
Read 2 more answers
A set of composite numbers less than 12 .express it in listing and set builder methods​
marusya05 [52]

Given:

A set of composite numbers less than 12.

To find:

The set by listing and set builder methods​.

Solution:

Composite number: A positive integer is called a composite number if it has at least one divisor other than 1 and itself.

Composite numbers less than 12 are 4, 6, 8, 9, 10.

By using the listing method , the given set can be expression as:

Set = {4, 6, 8, 9, 10}

The numbers 4, 6, 8, 9, 10 are greater than 1, less than 12 and non prime numbers.

By using set builder method, the given set can be expression as:

Set = \{x|x\neq P,1

Therefore, the list and set builder notation of the given set are {4, 6, 8, 9, 10} and \{x|x\neq P,1 respectively.

5 0
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