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WITCHER [35]
2 years ago
11

There are 1,023 M&M's in a bag. Out of 1,023 M&M's, 132 M&M's are blue, 69 are green, 68 are brown, 63 are olive, 62

are teal, 60 are navy, 56 are black, 55 are red, 54 are orange, 50 are yellow, 45 are lime, 45 are cyan, 44 are purple, 42 are magenta, 40 are gray, 40 are pink, 31 are apricot, 29 are beige, 24 are mint, and 14 are lavender. What is the probability that you pull 1 blue M&M in [...] amount of days, given that you are only allowed to pull 5 random M&M's per day, and there is no guarantee that you will pull 1 random M&M per day, assuming that you typically pull 1 to 3 random M&M's per day? Also, calculate the same probability if you pull 5 random M&M's per day.
Mathematics
1 answer:
lesantik [10]2 years ago
4 0

The probability that the person pulls 1 blue M&M given that one is only allowed to pull 5 random M&M's per day will be 0.6450.

<h3>How to calculate probability?</h3>

From the information given, there are 1,023 M&M's in a bag and out of 1,023 M&M's, 132 M&M's are blue.

Therefore, the probability of getting a blue M&M will be:

= 132/1023

= 0.1290

Therefore, since the person is given the chance to pull 5 random M&M's per day, the probability will be:

= 0.1290 × 5

= 0.6450

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

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Step-by-step explanation:

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3 years ago
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4.
valkas [14]

Answer: \boxed{y=\frac{4}{5}x-2}

Step-by-step explanation:

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Substituting into point-slope form,

y-6=\frac{4}{5}(x-10)\\\\y-6=\frac{4}{5}x-8\\\\\boxed{y=\frac{4}{5}x-2}

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2 years ago
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Answer:

The answer is 91.

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:)

6 0
2 years ago
What is the value of the expression?<br><br> (5/2)2+3/4^3
wel
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