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9966 [12]
4 years ago
12

Question 3. Multiply. (x + 5)(2x - 6).

Mathematics
1 answer:
andreev551 [17]4 years ago
5 0

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>D</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

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Help plz..And No links!! I repeat No links!!
nevsk [136]

I believe the answer to this is:

8:<u>35</u>

<u />

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8 0
3 years ago
32 divided by 4 equals what
Serggg [28]
32 divided by 4 is equal to 8
5 0
3 years ago
Read 2 more answers
135 in the ratio of 9:6
stepladder [879]

Step-by-step explanation:

9x+6x=135

15x=135

x=9

9x=81

6x=54

7 0
3 years ago
Whoever gets this right will get a brainiest and a good rating
zzz [600]

Answer:

The radius and the diameter of the circle are 11 cm and 22 cm respectively.

Step-by-step explanation:

The radius of a circle is a line segment extending from the center of a circle or sphere to the circumference or bounding surface, while the diameter of a circle is a straight line passing from side to side through the center of a body or figure, commonly a circle or sphere. Since the diameter goes entirely across the circle while passing through the midpoint - or center - of a circle and the radius only goes from the edge to the midpoint, that means the diameter is twice as big as the radius. In this example, the radius is already given to you, which is 11 cm, based on the image. Using this, you can figure out the diameter of that circle would be 11 * 2 or 22 cm. So the radius of the circle is 11 cm, while the diameter of the circle is 22 cm.

8 0
3 years ago
Read 2 more answers
What is an<br> equation of the line that passes through the points (-4, -3) and<br> (3, -3)?
Alex73 [517]

Answer:

y=-3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-3-(-3))/(3-(-4))

m=(-3+3)/(3+4)

m=0/7

m=0

y-y1=m(x-x1)

y-(-3)=0(x-(-4))

y+3=0(x+4)

y+3=0

y=0-3

y=-3

7 0
3 years ago
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