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3 years ago

Can anyone answer these (simplify to find the quotients)

Mathematics

1 answer:

Marina CMI [18]3 years ago

3 0

Here you go!! Hope this helps

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-2(n-3)

statuscvo [17]

Answer:

the minus can get inside the brackets

Step-by-step explanation:

-2(n-3)= 2(3-n)= 6-2n

7 0

3 years ago

Read 2 more answers

What is the remainder when the polynomial f(x)=3x^3-4x^2+2x+8 is divided by (x-5)

allsm [11]

Answer:

remainder = 290

Step-by-step explanation:

$\frac{3x^3-4x^2+2x+8}{x-5}$

= 3x² + 11x + 57 + $\frac{290}{x-5}$

quotient = 3x² + 11x + 57 and remainder = 290

6 0

3 years ago

The volume of a spherical balloon is increasing at the rate of 25cm^3/min, how fast is the radius increasing when the radius is

S_A_V [24]

Answer:

So the radius is increasing at $\frac{1}{64\pi} \frac{\text{cm}}{\text{min}}$ .

This is approximately 0.00497 cm/min that the radius is increasing.

Step-by-step explanation:

$V=\frac{4}{3}\pi r^3$

The volume and radius are both things that are changing with respect to time.

So their derivatives will definitely not be 0.

Let's differentiate:

$V'=\frac{4}{3} \pi \cdot 3r^2r'$

I had to use constant multiple rule and chain rule.

We are given $V'=+25 \frac{\text{cm^3}}{\text{min}}$ and $r=20 \text{cm}$ .

We want to find $r'$ .

Let's plug in first:

$25=\frac{4}{3}\pi \cdot 3(20)^2r'$

$25=\frac{4}{3} \pi \cdot 3(400)r'$

$25=\frac{4}{3} \pi \cdot 1200r'$

Multiply both sides by 3:

$75=4 \pi \cdot 1200r'$

$75=4800 \pi r'$

Divide both sides by $4800 \pi$ :

$\frac{75}{4800 \pi}=r'$

$\frac{1}{64 \pi}=r'$

So the radius is increasing at $\frac{1}{64\pi} \frac{\text{cm}}{\text{min}}$ .

This is approximately 0.00497 cm/min that the radius is increasing.

5 0

4 years ago

Read 2 more answers

Did I get all of the questions right?

Ymorist [56]

I believe you did but if you need help feel free to chat with me

5 0

4 years ago

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Teresa wrote this expression to describe the total distance she was going to swim during two swim classes.

frez [133]

I think the answer is the second one, Tessa wasn't sure how far she would swim during the first class. She would swim 3 laps during the second class. The question is confusing, because the equation s+3 is supposed to be the DISTANCE she swam in 2 classes. The problem didn't specify that distance equals laps, but I think the answer is correct

5 0

4 years ago