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Ilia_Sergeevich [38]
3 years ago
6

Can anyone answer these (simplify to find the quotients)

Mathematics
1 answer:
Marina CMI [18]3 years ago
3 0
Here you go!! Hope this helps

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-2(n-3)
statuscvo [17]

Answer:

the minus can get inside the brackets

Step-by-step explanation:

-2(n-3)= 2(3-n)= 6-2n

7 0
3 years ago
Read 2 more answers
What is the remainder when the polynomial f(x)=3x^3-4x^2+2x+8 is divided by (x-5)
allsm [11]

Answer:

remainder = 290

Step-by-step explanation:

\frac{3x^3-4x^2+2x+8}{x-5}

= 3x² + 11x + 57 + \frac{290}{x-5}

quotient = 3x² + 11x + 57 and remainder = 290


6 0
3 years ago
The volume of a spherical balloon is increasing at the rate of 25cm^3/min, how fast is the radius increasing when the radius is
S_A_V [24]

Answer:

So the radius is increasing at \frac{1}{64\pi} \frac{\text{cm}}{\text{min}}.

This is approximately 0.00497 cm/min that the radius is increasing.  

Step-by-step explanation:

V=\frac{4}{3}\pi r^3

The volume and radius are both things that are changing with respect to time.

So their derivatives will definitely not be 0.

Let's differentiate:

V'=\frac{4}{3} \pi \cdot 3r^2r'

I had to use constant multiple rule and chain rule.

We are given V'=+25 \frac{\text{cm^3}}{\text{min}} and r=20 \text{cm}.

We want to find r'.

Let's plug in first:

25=\frac{4}{3}\pi \cdot 3(20)^2r'

25=\frac{4}{3} \pi \cdot 3(400)r'

25=\frac{4}{3} \pi \cdot 1200r'

Multiply both sides by 3:

75=4 \pi \cdot 1200r'

75=4800 \pi r'

Divide both sides by 4800 \pi:

\frac{75}{4800 \pi}=r'

\frac{1}{64 \pi}=r'

So the radius is increasing at \frac{1}{64\pi} \frac{\text{cm}}{\text{min}}.

This is approximately 0.00497 cm/min that the radius is increasing.  

5 0
4 years ago
Read 2 more answers
Did I get all of the questions right?
Ymorist [56]
I believe you did but if you need help feel free to chat with me
5 0
4 years ago
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Teresa wrote this expression to describe the total distance she was going to swim during two swim classes.
frez [133]
I think the answer is the second one, Tessa wasn't sure how far she would swim during the first class. She would swim 3 laps during the second class. The question is confusing, because the equation s+3 is supposed to be the DISTANCE she swam in 2 classes. The problem didn't specify that distance equals laps, but I think the answer is correct
5 0
4 years ago
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