The height is 11.6 ft.

Z-scores are given by the formula

z=(X-μ)/σ

which in this situation leads us to

-0.5=(X-12.5)/1.8

Multiply both sides by 1.8:
-0.5(1.8) = ((X-12.5)/1.8)*1.8
-0.9 = X-12.5

Add 12.5 to both sides:
-0.9+12.5=X-12.5+12.5
11.6=X

5 0

4 years ago

Mattie Evans drove 80 miles in the same amount of time that it took a turbopropeller plane to travel 400 miles. The speed of the

PtichkaEL [24]

There is not a real way to justify this, but I saw first that 400-80 equals 320 which is double 160. This made me think that the period of time during this was 2 hours. The car drove 80 miles in two hours and the plane flew 400 miles in 2 hours. The period for one hour would be 40 mph for the car and 200 mph for the plane. 200-40=160. I have no idea how to prove it though and I’m hoping you can go backwards.

4 0

3 years ago

LLoyd used 1/4 of chocolate to make 2/3 gallons of chocolate pudding. If Lloyd's recipe is for 1 gallon of pudding, how many pou

Evgesh-ka [11]

Answer:

1/8

Step-by-step explanation:

Llyod used 1/4 chocolates to make 2/3 gallons of chocolate pudding

= 1/4 ÷ 2/3

= 1/4 × 3/2

= 3/8

Therefore the number of pounds needed to make 1/3 of the recipe can be calculated as follows.

= 3/8 × 1/3

= 3/24

= 1/8

5 0

3 years ago

A batch of 400 containers for frozen orange juice contains 5 that are defective. Two are selected, at random, without replacemen

zavuch27 [327]

Answer:

0.0100250

0.0001566

0.0000009445555

Step-by-step explanation:

Given the following :

Total number of containers = 400

Number of defective oranges = 5

2 are randomly selected without replacement :

A.) What is the probability that the second one selected is defective given that the first one was defective?

Since selection is without replacement and given that the first pick is defective ; number of defective oranges left = 4 ; total oranges left in container = (400 - 1) = 399

Hence,

Probability = (required outcome / Total possible outcomes)

P(2nd defective given 1st is defective) = 4 / 399

27. What is the probability that both are acceptable?

This means probability that both picks aren't defective.

Ist pick = 1 - P(defective) = (1 - (395/400) = 0.0125

2nd pick = 1 - P(defective) 1 - (394/399) = 0.0125313

.Hence, 0.0125 × 0.0125313 = 0.0001566

28. If three are selected without replacement, what is the probability that all three are defective?

1st pick = 5 / 400 = 0.0125

2nd pick = 4 / 399 = 0.0100250

3rd pick = 3 / 398 = 0.0075376

Hence, (0.0125 × 0.0100250 × 0.0075376) = 0.0000009445555

5 0

3 years ago