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3 years ago

Please show process!!!! THANK YOU! Will mark brainylist

Mathematics

1 answer:

lakkis [162]3 years ago

3 0

Answer: 103 degrees

Step-by-step explanation:

51 + 26 = 77

A triangle adds up to 180 degrees

180 - 77 = 103

= <u>103 degrees</u>

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Imagine two line segments where each represents a slant height of the cone. The segments are on opposite sides of the cone and m

noname [10]

Imagine that we cut the cone in half with a vertical plane. In this plane we'd see points a, b and c. We need to find the measure of angle bca, and then double that angle, to obtain the answer to this problem.

Note that tan (angle bca) = opp / adj = 2 / 6, or 1/3, or 0.333...

Working backwards to find angle bca, we use the inverse tangent function:

arctan 0.3333.. = approx. 0.322 radians, or 18.435 degrees.

Doubling that gives us the measurement of the angle formed between the line segments: 2(18.435 deg) = 36.9 degrees, approximately.

5 0

3 years ago

Read 2 more answers

You are designing a rectangular poster to contain 7575 in2 of printing with a 33-in margin at the top and bottom and a 11-in m

erma4kov [3.2K]

Answer:

The dimensions of the rectangular poster is 15 in by 5 in.

Step-by-step explanation:

Given that, the area of the rectangular poster is 75 in².

Let the length of the rectangular poster be x and the width of the rectangular poster be y.

The area of the poster = xy in².

$\therefore xy=75$

$\Rightarrow y=\frac{75}{x}$ ....(1)

1 in margin at each sides and 3 in margin at top and bottom.

Then the length of printing space is= (x-2.3) in

=(x-6) in

The width of printing space is = (y-2.1) in

=(y-2) in

The area of the printing space is A =(x-6)(y-2) in²

∴ A =(x-6)(y-2)

Putting the value of y

$\Rightarrow A =(x-6)(\frac{75}{x}-2)$

$\Rightarrow A = 87-\frac{450}{x}-2x$

Differentiating with respect to x

$A '= \frac{450}{x^2}-2$

Again differentiating with respect to x

$A''=-\frac{900}{x^3}$

To find the minimum area of printing space, we set A' = 0

$\therefore \frac{450}{x^2}-2=0$

$\Rightarrow 450 =2x^2$

$\Rightarrow x^2=225$

$\Rightarrow x=\pm 15$

Now putting x=±15 in A''

$A''|_{x=15}=-\frac{900}{15^3}$

$A''|_{x=-15}=-\frac{900}{(-15)^3}=\frac{900}{(15)^3}>0$

Since at x=15 , A"<0 Therefore at x=15 , the area will be minimize.

From (1) we get

$y=\frac{75}{x}$

Putting the value of x

$y=\frac{75}{15}$

=5 in

The dimensions of the rectangular poster is 15 in by 5 in.

4 0

3 years ago

CORRECT ANSWER GETS BRAINLIEST A frequency table of grades has five classes (A, B, C, D, F) with frequencies of 4,11 ,15 ,

ra1l [238]

Answer:

A = 10.5%

B = 28.9%

C = 39.5%

D = 18.4%

F = 2.6%

Step-by-step explanation:

Add all the frequencies together = 38

4/38 × 100 = 10.5%
11/38 × 100 = 28.9%
15/38 × 100 = 39.5%
7/38 × 100 = 18.4%
1/38 × 100 = 2.6%

10.5 + 28.9 + 39.5 + 18.4 + 2.6 = 100%

5 0

3 years ago

Which shows the prime factorization of 36?

leva [86]

A= 24
b= 36
c= 36
d= 54

3 0

3 years ago

I need help please and thank you

andrew-mc [135]

Answer:

Area will be 2(lb + bh + hl)

So 2*(12*9 + 9*4 + 4*12)

384 sqft

3 0

3 years ago

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