A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:
5 1/3 / 7 1/3 = 0.7272
Now rewrite the fraction as decimals:
2/3 = 0.667
¾ = 0.75
5/9 = 0.555
The closest scale that would still fit the frame would be 2/3 because it is under 0.727.
B. How much extra space is there in the frame when she uses the reduction from Part A?
Multiply the original size by the scale factor to use:
7 1/3 x 2/3 = 4 8/9
Now subtract the scaled size from the original size:
7 1/3 – 4 8/9 = 2 4/9 inches extra
C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?
Convert the scale from part A to a fraction:
0.72 = 72/99 which reduces to 8/11
Answer:
its 20 inches
Step-by-step explanation:
Suppose the students who scored 85 and 90 on the math test take the test again and score 95. How many stars would you have to add to the picturegraph next to 95?
10
Answer:
non-linear
Step-by-step explanation:
Answer:
F = $13,802.31
she can finance $13,802.31 with this loan.
Step-by-step explanation:
Given;
Rate r = 7% = 0.07
Time t = 4 years
Payment per month MP = $250
Number of months per year n = 12
This can be solved using compound interest for future value series formula;
F = future value
F = MP(((1 + r/n)^(nt) - 1)/(r/n))
Substituting the given values, we have;
F = $250(((1 + 0.07/12)^(12×4) - 1)/(0.07/12))
F = $13,802.31
