Question

Question 8 of 40

Answer 1

Answer:

$D.\:\left(x-3\right)\left(x+6\right)$

Step-by-step explanation:

$x^2 + 3x - 18$

$\left(x^2-3x\right)+\left(6x-18\right)$

$\left(x^2-3x\right):x\left(x-3\right)$

$\left(6x-18\right):6\left(x-3\right)$

$x\left(x-3\right)+6\left(x-3\right)$

Factor, common term:- x-3

$\left(x-3\right)\left(x+6\right)$

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