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yKpoI14uk [10]
2 years ago
12

Question Progress

Mathematics
1 answer:
MaRussiya [10]2 years ago
3 0
I think the area of the parallelogram is 260 cm squared. You multiply the 13 by the 20 to get 260. You don’t use the 15 because it is at an angle and you can’t get a proper height using it.
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Help me for f???????????
RSB [31]
The number decreases. 
8 0
3 years ago
Help meh?
zloy xaker [14]
X= # of miles
.55x+1.75 is greater than or equal to 10

So if she has to go more than 2 miles we will put 2 in for X

.55(2)+1.75 is greater than or equal to 10
.55×2= 1.10+1.75= 2.85
2.85 is greater than 10 is false so now we know she has to go more than 2 miles.

Let's guess and check. Now let's say 15 miles
.55×15= 8.25+1.75= 10
10=10 So she needs to drive at least 15 miles

x is greater than or equal to 15

Please don't solely rely on my answer I don't know if it's correct
3 0
3 years ago
Brandon buys a radio for $43.99 in a state where the sales tax is 7% what is the total Brandon pays for the radio?
babymother [125]
An increase by a percentage equal 1+percentage value multiplied by the original value.
7%=0.07
1+0.07=1.07
$43.99(1.07)=$47.0693
Round that to two decimal spaces.
$47.07
7 0
3 years ago
PLEASE HELP ASAP!!! WILL GIVE BRAINLIEST!!! PLEASE DON'T GUESS!!!
Aneli [31]
Hope this helps you understand

3 0
3 years ago
Read 2 more answers
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
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