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spayn [35]
3 years ago
11

How can systems of linear equations be used in real life?

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

Answer:

Almost any situation where there is an unknown quantity can be represented by a linear equation, like figuring out income over time, calculating mileage rates, or predicting profit. Many people use linear equations every day, even if they do the calculations in their head without drawing a line graph.

Step-by-step explanation:

Hope it is helpful....

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A principal of $1800 is invested at 8.5% interest, compounded annually. How much will the investment be worth after 11 years?
posledela
Calc= 1800 times (0.085 ^11)
3 0
2 years ago
How many solutions are there to this system of equations?
Zinaida [17]

Answer:

one

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP IM STRUGGLING!!!​
Mnenie [13.5K]

Answer:

  • 10. 0.99
  • 11. -60
  • 12. 5.5

Step-by-step explanation:

<u>Use the slope formula:</u>

  • m = (y2 - y1)/(x2 - x1)

10.

  • m = (6.24 - 3.27)/(5 - 2) = 2.97/3 = 0.99

11.

  • m = (240 - 360)/(3 - 1) = -120/2 = -60

12.

  • m = (8.84 - 6.09)/(7 - 2) = 2.75/5 = 5.5
6 0
3 years ago
Hey can you please help me posted picture of question
jenyasd209 [6]

The equation of parabola is x=ay^2. If a is positive and y^2 is always greater than zero or equal to zero, then x is also greater or equal to zero. This means that parabola is determined for non-negative x and for all real y.

Tha canonical equation of parabola is y^2=2px, where p>0. The branches of this parabola go up in positive y-direction. When you change x to y and y to x, then the branches of parabola go in positive x-direction, that is right.

Answer: correct choice is A.

6 0
3 years ago
Verify the identity<br><br>​
Oxana [17]

Answer:

see below

Step-by-step explanation:

sin x                                 1

-------------------              = -----------

sec^2 x - tan ^2 x               csc x

Sec = 1/cos   and tan = sin/cos

sin x                                         1

-------------------                     = -----------

1/ cos ^2 x -sin^2/cos ^2 x       csc x

Factor the denominator

sin x                                         1

-------------------                     = -----------

(1-sin^2 x)/ cos ^2 x                csc x

We know that 1 - sin^2 x = cos ^2

sin x                                         1

-------------------                     = -----------

(cos^2 x)/ cos ^2 x                csc x

sin x                                         1

-------------------                     = -----------

1                                               csc x

Multiply the top and bottom of the left hand side by 1/ sin x

sin x  * 1/ sin x                              1

-------------------                     = -----------

1     * 1 sin x                             csc x

1                                                1

-------------------                     = -----------

       1 sin x                             csc x

We know that 1/sin x = csc

1                              1

---------               = -----------

csc (x)                   csc x

3 0
3 years ago
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