Answer:
There was a 1.93% probability of having multiples (twins or more) in 1980.
Step-by-step explanation:
There were 3,612,258 births in the US in 1980.
Of those,
68339 + 1337 = 69676 were multiplies.
So
What was the probability of having multiples (twins or more) in 1980?
There was a 1.93% probability of having multiples (twins or more) in 1980.
Answer:
1) 6
2)4
3)27
4)126
5)15
Step-by-step explanation:
1. We need to see how many 8-miles are in 24 miles, than multiple it with 2in.
(24/8)*2=3*2=6in
2. Fist we calcue how many 17-feets are in 68feets, and multiple that with 1in.
(68/17)*1=4
3. We first see how many 3ins are in 9ins, and than multiple that with 9feet
(9/3)*9=3*9=27
4. First see how many 2ins are in 36ins, and then multiple it with 7.
(36/2)*7=18*7=126feet
5. See how many 15fts are in 75ft And than multiple it with 3.
(75/15)*3=5*3=15
You can eliminate 81 because we know 
The dot is on approximately 9.32 (my estimate) so I would square that number:
(9.32)² = 86.8624 so if you round this you get 87
Answer:
1680 ways
Step-by-step explanation:
Total number of integers = 10
Number of integers to be selected = 6
Second smallest integer must be 3. This means the smallest integer can be either 1 or 2. So, there are 2 ways to select the smallest integer and only 1 way to select the second smallest integer.
<u>2 ways</u> <u>1 way</u> <u> </u> <u> </u> <u> </u> <u> </u>
Each of the line represent the digit in the integer.
After selecting the two digits, we have 4 places which can be filled by 7 integers. Number of ways to select 4 digits from 7 will be 7P4 = 840
Therefore, the total number of ways to form 6 distinct integers according to the given criteria will be = 1 x 2 x 840 = 1680 ways
Therefore, there are 1680 ways to pick six distinct integers.
They will ring again together at 10:15am. Because the common factor for 40, 48 and 60 is 240, which means 240 minutes, that equals to 4 hours. Hence 4 hours after 6.15am is 10.15am.
Hope this helps.
