Answer:
a. 0.76
b. 0.23
c. 0.5
d. p(B/A) is the probability that given that a student has a visa card, they also have a master card
p(A/B) is the probability that given a student has a master card, they also have a visa card
e. 0.35
f. 0.31
Step-by-step explanation:
a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)
=0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76
b. P(AnBnC')= P(AnB)-P(AnBnC)
=0.3-0.07= 0.23
c. P(B/A)= P(AnB)/P(A)
=0.3/O.6= 0.5
e. P((AnB)/C))= P((AnB)nC)/P(C)
=P(AnBnC)/P(C)
=0.07/0.2= 0.35
f. P((AUB)/C)= P((AUB)nC)/P(C)
=(P(AnC) U P(BnC))/P(C)
=(0.11+0.1)/0.2
=0.21/0.2 = 0.31
M = (y2-y1)/(x2-x1)
= (4-14)/3-1
= -10/2
= -5
Answer:
24 x 24 x 25 x 710 = 10,224,000
Step-by-step explanation:
24 x 24 = 576
576 x 25 = 14, 400
14,400 x 710 = 10,224,000
lo que da en total= 10,224,000
The measure of ∠1 is also <span>93° because vertically opposite angles are equal.</span>
The "relative frequency" is
(number of times a blue marble came out)
divided by
(total number of trials before everybody got bored and quit) .
-- The relative frequency of blue was (20/60) = (33 and 1/3) % .
(Even though 38.5% of the marbles in the jar are blue,
they didn't get picked that often.)
-- The relative frequency of green was (18/60) = 30 % .
(Even though only 26.9% of the marbles in the jar are green,
they got picked more often than that.)
-- The relative frequency of red was (22/60) = (36 and 2/3) % .
(Even though 42.3% of the marbles in the jar are red,
they didn't get picked that often.)
