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sammy [17]
3 years ago
5

Gina willson all about algebra (TRIANGLES ANGLES SUM) HELP ASAP PLEASE

Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

14. Question wise,

In ΔRST,

∠R=2x+5

∠S=x+1

∠T=7x-16

we know,

∠R+∠S+∠T=180 [sum of 3 angles of a triangle is 180°]

2x+5+x+1+7x-16=180

10x-10=180

10(x-1)=180

x-1=18

x=19

so,

∠R=(2×19)+5=43

∠S=19+1=20

∠T=(7×19)-16=117

15. Question wise,

In ΔABC,

∠A=∠C-13

∠B=4∠C-11

we know,

∠A+∠B+∠C=180 [,,]

∠C-13+4∠C-11+∠C=180

6∠C-24=180

6∠C=180+24

∠C=204÷6=34

so,

∠A=34-13=21

∠B=(4×34)-11=125

16. Question wise,

In ΔJKL

∠K=∠J+9

∠L=2∠J-21

we know,

∠J+∠K+∠L=180

∠J+∠J+9+2∠J-21=180

4∠J-12=180

4∠J=180+12

∠J=192÷4=48

so,

∠K=48+9=57

∠L=(2×48)-21=75

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What is the value of t?
Lilit [14]

Hey!

-------------------------------------------------

I'm going to assume that the value of t is x.

-------------------------------------------------

Steps To Solve:

3(x - 2) = 6

~Distributive Property

→ 3x - 6 = 6

~Simplify

→ 3x + (-6) = 6

~Add 6 to both sides

→ 3x + (-6) + 6 = 6 + 6

~Simplify

→ 3x = 12

~Divide 3 to both sides

→ 3x/3 = 12/3

~Simplify

→ x = 4

-------------------------------------------------

Hence, x equals 4!

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Hope This Helped! Good Luck!

8 0
3 years ago
Julie planted a rectangular garden that is 20 feet long. She placed 56 feet of fencing around her garden. Draw and label a sketc
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See attached picture for response.

5 0
3 years ago
PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0
2 years ago
Can anyone help me ASAP!
igomit [66]

Answer:

7.8

Step-by-step explanation:

the answer is

\sqrt{61}

3 0
3 years ago
Given f(x)=x-8 find f(1)+10
Ronch [10]

Answer:

3

Step-by-step explanation:

replace all x variables with 1 and solve that equation ; f(x)=x-8 so.... f(x) = 1-8

there for f(1)=-7

now, add -7 and 10 for your answer:

f(1)+10= 3

6 0
3 years ago
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