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2 years ago

A point is chosen at random on AK what is the probability that one point will be on BG?

Mathematics

1 answer:

kobusy [5.1K]2 years ago

7 0

Answer:

11/21.

BG has a total of 11 points (when you include 0), and there are 21 points total. 11/21 cannot be simplified, your final answer is 11/21.

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0.985 rounded to the nearest tenth

GarryVolchara [31]

They always try to trick you with this. Remember anything 5 or above would round up, anything 4 and under would round down. So look for the tenth place. that's the 9. The number to the right is 8 which is greater than 5. That means round up. You can't round it to 0.1 because that takes it back down. So you just move it over. The answer is 1.0.

8 0

3 years ago

The population of a certain city was 112,000 in 1998, and the observed relative growth rate is 4% per year. (a) Find a function

Zanzabum

Answer:

See Explanation

Step-by-step explanation:

Now;

From;

P=Poe^kt

Where;

P = population at time=t

Po = population initially present

k = growth rate

t = time taken

a) The function is;

P= 112,000e^0.04t

b) In the year 2004, the population will be

P= 112,000e^0.04(6)

P= 142380

c) 200,000 =112,000 e^0.04t

200,000/112,000 = e^0.04t

1.786 = e^0.04t

ln 1.786 = ln e^0.04t

ln 1.786= 0.04t

t = ln 1.786/0.04

t = 14.5 years

6 0

2 years ago

A triangle has sides with lengths of 8 millimeters, 11 millimeters, and 14 millimeters. Is it a right triangle?

Burka [1]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

At 12 noon a ship going due east at 12 knots crosses 10 nautical miles ahead of a second ship going due north at 16 knots

mixas84 [53]

6t-10is the awsner. If s is the number of nautical miles separating the ships, express s in terms of t(the number of hours after 12 noon). I formed the equation s squared to the second power equals (12t) squard to the second power + (10 - 16) squared to the second power

7 0

3 years ago

Nina and Jo both ran an 8 km race. Nina took 55 minutes to run the whole race. Jo started the race 3 minutes later than Nina but

grin007 [14]

Answer:

Step-by-step explanation:

First we figure out how fast Nina can run. If Nina can run 8 km in 55 minutes, then her rate is

$\frac{8km}{55min}=.145\frac{km}{min}$ and we can use that in a d = rt table:

d = r * t

Nina .145

Now we can fill in the distance which is 6 for both, since that is the distance where they met:

d = r * t

Nina 6 = .145

Jo 6 =

Now we go to the info given about the time. If Jo started the race 3 minutes after Nina, that means that Nina is running 3 minutes longer than Jo. Filling in the time info:

d = r * t

Nina 6 = .145 * t + 3

Jo 6 = r * t

As you can see, right now we have 2 unknowns in Jo's row. But we don't have to! We will go to Nina's row where the only unknown is time and solve for t. If d = rt, then

6 = .145(t + 3) and

6 = .145t + .435 and

5.55 = .145t so

t = 38.379 minutes. This means that Jo was running 38.379 minutes when she caught up to Nina (it took Nina 3 minutes longer than that to go 6 km since she was already running for 3 minutes when Jo started the race). If Jo's time is 38.379, we can use that in her row for t and solve for r. If d = rt, then

6 = r(38.379) and

r = .16 km/min

Let's check it without the rounding (rounding takes away from the accuracy). If 6 = .145(t + 3) and Nina's rate not rounded is .145454545 and t = 38.37931034, then, rewriting without rounding:

6 should equal .145454545( 38.37931034 + 3)

6 ?=? .145454545(41.37931034)

6 ?=? 6.0 so

Jo's rate is .16 km/min rounded

6 0

2 years ago