Ask question

Ask question

All categories

3 years ago

11

Please help me with ALL WORK SHOWN!! I will give you 15 points

1 answer:

max2010maxim [7]3 years ago

4 0

Answer:

What are the major problems of cotton textile industries? first answer this

You might be interested in

After reading The Lord of the Rings, Francesca signs up for archery lessons. At her first lesson, she sets up her target 5 feet

N76 [4]

Answer:

$3$ times

Step-by-step explanation:

$5x=15$

Divide both sides by 5

$x=3$

Hope this helps

6 0

3 years ago

Read 2 more answers

The curve is the graph of function f. Use the graph to find the value of the function for the following values of x: -2,-.5,0,2.

VikaD [51]

Answer:

1, 0.75, 1.25, 3, 0

Step-by-step explanation:

To find the value of the function, we find the y coordinate of the point with the given x value.

7 0

2 years ago

How do you write three hundred four million,eight hundred thousand,four hundred

Katena32 [7]

300,800,400
Million, thousand, hundred

5 0

3 years ago

Directions: Find the complemen

andre [41]

Given:

The angles are:

Example $54^\circ$

1. $63^\circ$

2. $87^\circ$

3. $45^\circ$

4. $72^\circ$

5. $5^\circ$

To find:

The complimentary angle of the given angles.

Solution:

If two angles are complimentary, then their sum is 90 degrees.

Example: Let x be the complimentary angle of $54^\circ$ , then

$x+54^\circ=90^\circ$

$x=90^\circ -54^\circ$

$x=36^\circ$

Similarly,

1. The complimentary angle of $63^\circ$ is:

$90^\circ -63^\circ=27^\circ$

2. The complimentary angle of $87^\circ$ is:

$90^\circ -87^\circ=3^\circ$

3. The complimentary angle of $45^\circ$ is:

$90^\circ -45^\circ=45^\circ$

4. The complimentary angle of $72^\circ$ is:

$90^\circ -72^\circ=18^\circ$

5. The complimentary angle of $5^\circ$ is:

$90^\circ -5^\circ=85^\circ$

Therefore, the complimentary angles of $54^\circ, 63^\circ, 87^\circ, 45^\circ, 72^\circ, 5^\circ$ are $36^\circ, 27^\circ, 3^\circ, 45^\circ, 18^\circ, 85^\circ$ respectively.

6 0

3 years ago

Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated

koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.

With this, you will need to use the distance formula, $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , on XY, YZ, and ZX.

XY: $\sqrt{(3-1)^2+(1-6)^2}$

Firstly, solve inside the parentheses: $\sqrt{(2)^2+(-5)^2}$

Next, solve the exponents: $\sqrt{4+25}$

Next, solve the addition, and XY's distance will be √29

(The process is the same with the other 2 sides, so I'll go through them real quickly)

YZ:

$\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}$

ZX:

$\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}$

Now that we got the 3 sides, we can add them up: $\sqrt{29}+\sqrt{13} +\sqrt{34} =14.8$

In short, your answer is 14.8, or the second option.

8 0

3 years ago