![\bf A=\cfrac{1}{2}20h\implies A=\cfrac{20h}{2}\implies A=10h](https://tex.z-dn.net/?f=%5Cbf%20A%3D%5Ccfrac%7B1%7D%7B2%7D20h%5Cimplies%20A%3D%5Ccfrac%7B20h%7D%7B2%7D%5Cimplies%20A%3D10h)
now, the
range for that equation is all real numbers, is a linear equation and therefore will pass the "vertical line test" and thus be a one-to-one function, and therefore will have an
inverse function.
for a function that has an inverse function, the
range of the original function is exactly the same as the
domain for its inverse. Therefore, if the range of that function is all real numbers, then the domain of its inverse is just that.
what's the inverse, well, let's do the switcharoo.
![\bf A=10h\qquad inverse\implies \boxed{h}=10\boxed{A}\impliedby A^{-1}(h)](https://tex.z-dn.net/?f=%5Cbf%20A%3D10h%5Cqquad%20inverse%5Cimplies%20%5Cboxed%7Bh%7D%3D10%5Cboxed%7BA%7D%5Cimpliedby%20A%5E%7B-1%7D%28h%29)
we are not solving for "h", because, well, is already solved for "h".
Answer:
20in²
Step-by-step explanation:
The area of a triangle is calculated using the formula A = bh/2
"A" means area.
"b" is for the base.
"h" is for the height.
It does not matter which is the base and which is the height, as long as they are perpendicular (at 90°) to each other.
5in can be the height.
8in can be the base.
Put the base and height measurements into the formula.
A = bh/2
A = (8in)(5in)/2 Multiply the measurements and the units.
A = (40in²)/2 Divide by 2
A = 20in² Area of the triangle
When you multiply units, in X in becomes in².
"in" has the exponents 1. When you multiply two "in" with exponent 1, you add the exponents. 1 + 2 = 2.
in¹ X in¹ = in¹⁺¹ = in²
Answer:
36 and 32
Step-by-step explanation:
So what you do is look at the radius which is 18. The radius is half the distance. So all you have to do is do 18*2=36.
Same with the other one 16*2=32.
Those are your answers.
Answer:
J(x)
Step-by-step explanation: