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STALIN [3.7K]
3 years ago
11

Please help me with ALL WORK SHOWN!! I will give you 15 points

Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

What are the major problems of cotton textile industries? first answer this

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After reading The Lord of the Rings, Francesca signs up for archery lessons. At her first lesson, she sets up her target 5 feet
N76 [4]

Answer:

3 times

Step-by-step explanation:

5x=15

Divide both sides by 5

x=3

Hope this helps

6 0
3 years ago
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The curve is the graph of function f. Use the graph to find the value of the function for the following values of x: -2,-.5,0,2.
VikaD [51]

Answer:

1, 0.75, 1.25, 3, 0

Step-by-step explanation:

To find the value of the function, we find the y coordinate of the point with the given x value.

7 0
2 years ago
How do you write three hundred four million,eight hundred thousand,four hundred
Katena32 [7]
300,800,400
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5 0
3 years ago
Directions: Find the complemen
andre [41]

Given:

The angles are:

Example 54^\circ

1. 63^\circ

2. 87^\circ

3. 45^\circ

4. 72^\circ

5. 5^\circ

To find:

The complimentary angle of the given angles.

Solution:

If two angles are complimentary, then their sum is 90 degrees.

Example: Let x be the complimentary angle of 54^\circ, then

x+54^\circ=90^\circ

x=90^\circ -54^\circ

x=36^\circ

Similarly,

1. The complimentary angle of 63^\circ is:

90^\circ -63^\circ=27^\circ

2. The complimentary angle of 87^\circ is:

90^\circ -87^\circ=3^\circ

3. The complimentary angle of 45^\circ is:

90^\circ -45^\circ=45^\circ

4. The complimentary angle of 72^\circ is:

90^\circ -72^\circ=18^\circ

5. The complimentary angle of 5^\circ is:

90^\circ -5^\circ=85^\circ

Therefore, the complimentary angles of 54^\circ, 63^\circ, 87^\circ, 45^\circ, 72^\circ, 5^\circ are 36^\circ, 27^\circ, 3^\circ, 45^\circ, 18^\circ, 85^\circ respectively.

6 0
3 years ago
Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated
koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.


With this, you will need to use the distance formula, \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, on XY, YZ, and ZX.



XY: \sqrt{(3-1)^2+(1-6)^2}


Firstly, solve inside the parentheses: \sqrt{(2)^2+(-5)^2}


Next, solve the exponents: \sqrt{4+25}


Next, solve the addition, and XY's distance will be √29



(The process is the same with the other 2 sides, so I'll go through them real quickly)


YZ:

\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}



ZX:

\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}



Now that we got the 3 sides, we can add them up: \sqrt{29}+\sqrt{13} +\sqrt{34} =14.8


In short, your answer is 14.8, or the second option.

8 0
3 years ago
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