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sveta [45]
2 years ago
15

A bag contains 4 g r e e n marbles, 8 b l a c k marbles, and 7 b l u e marbles. If a marble is drawn from the bag, replaced, and

another marble is drawn, what is the probability of drawing first a g r e e n marble and then a b l u e marble
Mathematics
1 answer:
nignag [31]2 years ago
4 0

Answer:

P(Green\ and\ Blue) = 0.0776

Step-by-step explanation:

Given

Green = 4

Black = 8

Blue=7

Required

Determine the probability of selecting green then blue marble

This probability is represented as:

P(Green\ and\ Blue)

And it is calculated using:

P(Green\ and\ Blue) = P(Green) * P(Blue)

P(Green\ and\ Blue) = \frac{n(Green)}{Total} * \frac{n(Blue)}{Total}

Total marble is:

Total = 4 + 8 + 7

Total = 19

So, we have:

P(Green\ and\ Blue) = \frac{4}{19} * \frac{7}{19}

P(Green\ and\ Blue) = \frac{4*7}{19*19}

P(Green\ and\ Blue) = \frac{28}{361}

P(Green\ and\ Blue) = 0.0776 -- approximated

<em>Hence, the required probability is approximately 0.0776</em>

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