Answer:
The first option is the correct option
Step-by-step explanation:
From the question the slope AC is evaluated as


And the slope of line CB is mathematically evaluated as


Now for lines that are perpendicular to each other then the product of their slope should be equal to -1
So if

Then

i,e
![[\frac{b}{a+ c} ] [\frac{b}{a-c} ] = -1](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bb%7D%7Ba%2B%20c%7D%20%5D%20%5B%5Cfrac%7Bb%7D%7Ba-c%7D%20%5D%20%3D%20-1)
Answer:
y = 1/3x - 1
Step-by-step explanation:
Given the slope of 1/3, and the point (-3, -2): we can plug these values into the slope-intercept form, y = mx + b where:
m = slope
b = y-coordinate of the y-intercept, (0, <em>b</em>)
y = mx + b
-2 = 1/3(-3) + b
-2 = -1 + b
Add 1 to both sides to solve for b:
-2 + 1 = -1 + 1 + b
-1 = b
The y-intercept is b = -1.
Therefore, given the slope, m = 1/3, and y-intercept, b = -1:
the linear equation in slope-intercept form is:
y = 1/3x - 1
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Answer:
70
Step-by-step explanation:
The angle is equal to the degree of the arc, so the angle, 2x, is equal to 140°.
140 = 2x
140/2 = x
70 = x
x is equal to 70.
Answer: 9.97
==============================================
Explanation:
y = distance from the base of the pole to the closest person
y+200 = total horizontal distance
-------------
Focus on the smaller right triangle.
tan(angle) = opposite/adjacent
tan(26) = 55/y
y*tan(26) = 55
y = 55/tan(26)
y = 112.76671 approximately
Make sure your calculator is in degree mode.
--------------
Now move to the larger right triangle
tan(angle) = opposite/adjacent
tan(x) = 55/(y+200)
tan(x) = 55/(112.76671+200)
tan(x) = 55/312.76671
tan(x) = 0.17585
x = arctan(0.17585) same as 
x = 9.97349
x = 9.97 degrees approximately