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2 years ago

Which term is a word for a fee that is paid for the use of another person's money?

Mathematics

2 answers:

KATRIN_1 [288]2 years ago

7 0

Answer:

Step-by-step explanation:

Zarrin [17]2 years ago

5 0

Answer:

Interest!

Step-by-step explanation:

The term that is used for a fee that is paid for with the use of another person's money is called interest. Interest is based on some percentage on which the lender lends you money.

(I researched it earlier)

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Given that (- 2, 7) is on the graph of f(x) , find the corresponding point for the function f(x + 4).

AveGali [126]

Answer:

$\boxed{\ the \ corresponding\ point\ is \ (-6,7)\ }$

Step-by-step explanation:

We know that f(-2)=7

x+4 = -2 <=> x = -6

so f(-6+4) = f(-2)=7

then the corresponding point is (-6,7)

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2 years ago

What is the missing numerator?

Jet001 [13]

The answer is b)04 I did this on my test and got it correct

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2 years ago

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Jane Rose’s semimonthly salary is $750. Her yearly salary is A.$9000 B. $12,500 C. $18,000 D. $19,500 E. $21,000

Lunna [17]

A because 750 times 12 because there is 12 months in a year. You get 9000

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2 years ago

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Find the area and round to the nearest hundredth??

bagirrra123 [75]

Answer:

total area = 193.31 m²

Step-by-step explanation:

rectangle area = 7 x 15 = 105 m²

semi circle area = (3.14)(7.5²)/2 = 88.31 m²

total area = 105 m² + 88.31 m² = 193.31 m²

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2 years ago

Evaluate cos(sin^-1(4/5)

PSYCHO15rus [73]

Step-by-step explanation:

$Let \: \: \theta = \sin^{ - 1} (\frac{4}{5}) \\ \\ \therefore \: \sin\theta = \frac{4}{5} \\ \\ \because \: { \cos}^{2} \theta =1 - { \sin}^{2} \theta \\ \\ \therefore \: { \cos}^{2} \theta = 1 - (\frac{4}{5} )^{2} \\ \\ = 1 - \frac{16}{25} \\ \\ = \frac{25 - 16}{25} \\ \\ = \frac{9}{25} \\ \\ \therefore \:{ \cos}\theta = \pm \: \frac{3}{5} \\ \\ \because \: \theta \: lie \: in \: the \: first \: quadrant \\ \\ \therefore \: { \cos}\theta = \: \frac{3}{5} \\ \\ \implies \theta = { \cos}^{ -1 } \: \frac{3}{5}\\\\\implies \theta = { \cos}^{ -1 } \: \frac{3}{5}= { \sin}^{ -1 } \: \frac{4}{5} \\ \\ \therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) \\ \\ = \cos( \ {cos}^{ - 1} \frac{3}{5} ) \\\\ = \frac{3}{5} \\ \\ \purple{ \boxed{\therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) = \frac{3}{5}}}$

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2 years ago