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torisob [31]
3 years ago
11

Help me with this pls thank you

Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0
It’s -2 if you are looking for the slope.
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Identify the restrictions on the domain of f(x) = x+2/x-3<br> x≠-2<br> x≠2<br> x≠-3<br> x≠3
erma4kov [3.2K]

Answer:

  x ≠ 3

Step-by-step explanation:

The denominator of ...

  f(x) = (x+2)/(x -3)

is zero when x=3, so the function is not defined there. Values of x for which the function is not defined are not part of the domain.

The restriction is: x ≠ 3.

_____

Please note that parentheses are required around numerators and denominators when a rational function is written in plain text. When it is typeset:

  f(x)=\dfrac{x+2}{x-3}

the division bar serves as a grouping symbol. In plain text, we cannot tell where numerator and denominator begin and end unless some other grouping symbol (parentheses) is used.

4 0
3 years ago
The amount of potential energy, P, an object has is equal to the product of its mass, m, its height off the ground, h, and the g
PIT_PIT [208]
H=P/mg is the solution
8 0
3 years ago
Read 2 more answers
Evaluate: ab for a = 2 and b = 5
Alona [7]

Answer:

10

Step-by-step explanation:

ab = a * b

if a is 2 and b is 5 then 2 * 5 = 10

3 0
3 years ago
Hey! I am here with some geometry questions today!
mrs_skeptik [129]

Answer:

  • Parallelogram

Step-by-step explanation:

  • ED = FG = 4, easy to calculate
  • ED ║ FG, both are vertical line segments
  • EF = DG = √5²+1²= √26
  • EF ║ DG as the slopes are same
  • m(EF) = (7-6)/(6-1) = 1/5
  • m(DG) = (3-2)/(6-1) = 1/5

As we see the opposite sides are parallel and congruent. This is the property of a parallelogram

8 0
3 years ago
2. Another wooden plank is leaning against an outside wall of a building. The bottom of the plank is 9 ft from the wall. The len
siniylev [52]
(A) Find the value of x. Round to the nearest tenth of a degree<span>
Given that the distance of the ground is 9ft.
Length of the plank is 41 ft

In order to get the angle formed between the ground and the foot of the plank,

cos (theta) = ground / plank
cos (theta) = 9 / 41
</span><span>cos (theta) = 0.21951...
</span>theta = cos^-1(<span>0.21951...)
</span><span>theta = 77.3 degrees

</span><span>(b) Find the height above the ground where the plank touches the wall. Round to the nearest tenth of a foot.
</span><span>
Height = square root (plank^2 - ground^2)
Height = square root (41^2 - 8^2)
</span><span>Height = square root (1600)
</span><span>Height = 40

(A) 77.1 Degrees
(B) 40 feet</span>
6 0
4 years ago
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