Help me with this pls thank you

Below is the graph of f ′(x), the derivative of f(x), and has x-intercepts at x = –3, x = 1 and x = 2. There are horizontal tang

mojhsa [17]

Answer:

C. f has a relative maximum at x = 1.

Step-by-step explanation:

A. False. f(x) is concave down when f"(x) is negative. f"(x) is the tangent slope of the graph, f'(x). So f(x) is concave down between x = -1.5 and x = 1.5.

B. False. f(x) is decreasing when f'(x) is negative. So f(x) is decreasing in the intervals x < -3 and 1 < x < 2.

C. True. f(x) has a relative maximum where f'(x) = 0 and changes from + to -.

8 0

3 years ago

Given that BD is the median of AABC and that AABC is isosceles, congruence postulate SSS can be used to prove which of the follo

marusya05 [52]

Answer:

B.

Step-by-step explanation:

Because of isosceles triangle, AB = CB.

Because of the median, AD = CD.

Because of congruence of segments being reflexive, BD = BD.

By SSS, the triangles BAD and BCD are congruent.

Answer: B.

7 0

2 years ago

g What is the probability of being dealt exactly three of a kind (like three kings or three 7’s, etc.) in a five card hand from

Elena L [17]

Answer: 0.02257

Step-by-step explanation:

Given : Total cards in a deck = 52

Number of ways to select any 5 cards : $^{52}C_5$

Since , there are total 13 kinds of card (includes Numbers from 2 to 9 and Ace , king, queen and jack).

Of each kind , there are 4 cards.

Number of ways to select three cards in a five card hand of a single kind : $^{4}C_3\times^{48}C_2$

Number of ways to select three cards in a five card hand of a exactly three of a kind : $13\times^{4}C_3\times^{48}C_2$

Now , the required probability = $\dfrac{13\times^{4}C_3\times^{48}C_2}{^{52}C_5}$

$=\dfrac{13\times4\times\dfrac{48!}{2!46!}}{\dfrac{52!}{5!47!}}\\\\\\=\dfrac{58656}{2598960}$

$=0.022569027611\approx0.02257$

∴ The probability of being dealt exactly three of a kind (like three kings or three 7’s, etc.) in a five card hand from a deck of 52 cards= 0.02257

8 0

3 years ago

Let f={(-1, 4),(1, 9),(4, 0)} and g={(-1, -8),(2, -7),(4, 8),(5, -9)}. Find g/f and state its domain.

tekilochka [14]

Answer:

g/f = {(-1, 2)}

domain of g/f = {-1}

Step-by-step explanation:

Given,

f = {(-1, 4),(1, 9),(4, 0)},

g = {(-1, -8),(2, -7),(4, 8),(5, -9)}

So, Domain of f = {-1, 1, 4},

Domain of g = {-1, 2, 4, 5}

Since,

$\frac{g}{f}(x) = \frac{g(x)}{f(x)}$

Thus, domain of g/f = Domain of f ∩ Domain of g = {-1, 4}

If x = -1,

$\frac{g}{f}(-1) = \frac{g(-1)}{f(-1)}=\frac{-8}{-4}=2$

If x = 4,

$\frac{g}{f}(4) = \frac{g(4)}{f(4)}=\frac{8}{0}=\infty (\text{ not possible})$

Hence, the domain of g/f = {-1}

And, g/f = {(-1, 2)}

4 0

3 years ago

Beth purchased 7 sandwiches and spent a total of $43.75. If each sandwich was the same price, what was the cost per sandwich?

Alexus [3.1K]

Answer:

6.25 dont fake ur grade plz

Step-by-step explanation:

6 0

3 years ago