Answer:
You are using <u>Commutative Property </u>
Step-by-step explanation:
(5/8)+(2/5)=
so you need a common den so in this case its 40
so we multiply to get 40 like
(5/5)(5/8)+ (2/5)(8/8)=
25/40 + 16/ 40 = 41/40
Answer:
0 < x ≤ 12 and 0 < y ≤ 36
Step-by-step explanation:
Here, x represents the number of female gazelles and y represents the number of male gazelles.
The zoo only has room for 12 female gazelles.
∵ The number of rooms must be more than or equal to the total female gazelles ,
12 ≥ x
Also, number of animals can not be negative,
And, it must be greater than 0.
⇒ 0 < x ≤ 12,
⇒ 3(0) < 3x ≤ 3(12)
⇒ 0 < 3x ≤ 36
∵ Number of males gazelles = 3 × number of female gazelles
⇒ y = 3x
⇒ 0 < y ≤ 36
Hence, the constraints to represent a thriving population of gazelles at the zoo are,
0 < x ≤ 12,
0 < y ≤ 36
Terms: -4j, -2, -5j, 6
Like Terms: -4j and -5j, -2 and 6
Coefficients: -4, -5
Constants: -2, 6
The area of this figure is 10
