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nignag [31]
2 years ago
7

Simplify: (2-2x5-5)-4

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
7 0

Answer:

(2*5^2)+4/3^2-5

(2*25)+4/3^2-5

50+4/3^2-5

50+1.7-5

46.7

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Part B if the height of each prism is 10 Cm what is the surface area prism
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Answer:

Prism A:

Area = 288cm^2

Prism B:

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Step-by-step explanation:

Given

See attachment for prisms

Height(h) = 10cm

Required

Determine the surface area of both prisms

Prism A is triangular and as such, the surface area is:

Area = 2 * A_b + (a + b + c) * h

Where

A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}

and

s = \frac{a + b + c}{2}

Such that a, b and c are the lengths of the triangular sides of the prism.

From the attachment;

a = 8; b =6; c =10

So, we have:

s = \frac{a + b + c}{2}

s = \frac{8 + 6 + 10}{2}

s = \frac{24}{2}

s = 12

Also:

A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}

A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}

A_b = \sqrt{576}

A_b = 24

So:

Area = 2 * A_b + (a + b + c) * h

Area = 2 * 24 + (8 + 6 + 10) * 10

Area = 288cm^2

Prism B is a rectangular prism. So, the area is calculated as:

Area = 2 * (ab + bh + ah)

From the attachment

a = b = 5

h =10

So:

Area =2 * (5 * 5 + 5 * 10 + 5 * 10)

Area =250cm^2

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