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sergeinik [125]
3 years ago
5

A single box of thumb racks weighed 3 1/ 2 ounces . If a teacher had 4 1/ 7 boxes how much would their combined weight be make s

ure to restate your answer in sentence form
Mathematics
1 answer:
DerKrebs [107]3 years ago
3 0

Answer:

36/7 or 5 1/7

Step-by-step explanation:

ok so first you have to change 3 1/2 and 4 1/7 into an improper fraction

then you get 7/2 and 29/7 then you have to change the denominators to 14 so it would be 14/14 or 1 an then 58/14 then you add 14/14 + 58/14

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viva [34]

For part A, turn 10x + 5y = 20 into slope intercept form. An equation with the same slope as Amanda’s equation will be linear. I hope this helps :)

6 0
3 years ago
Daniel wants to prove that the interior angles of any triangle sum to 180°. He draws a line through one vertex parallel to the o
Serggg [28]

Alternate interior angles theorem.

<u>Step-by-step explanation:</u>

By using the definition of Alternate Interior Angles theorem, we can say that If a transversal cuts any two parallel lines, then those pairs of alternate interior angles are seems to be  congruent.

So in the given triangle,

∠4 ≅ ∠2

∠5 ≅ ∠3

Sum of all the angles in a triangle = 180°

∠1 + ∠2 + ∠3 = 180°

Since from the above congruence, we can write that

∠1 + ∠4 + ∠5 = 180°

Hence proved.

4 0
3 years ago
Please urgent!!!!!!!!!!!!
Rus_ich [418]

Answer:

the last one

Step-by-step explanation:

6 0
2 years ago
Which of the following expressions could be equal to f(x)???
noname [10]
If i understand the machine correctly and -3 is x and 8 is the final answer, f(x)=x+11
4 0
2 years ago
Deshawn has two bags of marbles. The first bag has 2 blue, 3 orange, and 5 red. The second bag has 4 pink, 10 blue, and 6 brown.
madreJ [45]

Answer: 0.1

Step-by-step explanation:

Given

Bag-I has 2 blue,3 orange, 5 red

Bag-II has 4 Pink,10 blue, 6 brown

No of ways of choosing a blue marble from bag-I

\Rightarrow ^2C_1

Total no of ways of choosing a marble from bag-I

\Rightarrow ^{10}C_1

No of ways of choosing a blue marble from bag-II

\Rightarrow ^{10}C_1

Total no of ways of choosing a marble from bag-II

\Rightarrow ^{20}C_1

The probability that he will pull out a blue marble from each bag is

\Rightarrow P=\text{Probability of pulling a blue marble from bag-I}\times \text{Probability of pulling a blue out bag-II}

\Rightarrow P=\dfrac{^2C_1}{^{10}C_1}\times \dfrac{^{10}C_1}{^{20}C_1}\\\\\Rightarrow P=\dfrac{2}{10}\times \dfrac{10}{20}=\dfrac{1}{10}

3 0
3 years ago
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