First, you have to find the equation of the perpendicular bisector of this given line.
to do that, you need the slope of the perpendicular line and one point.
Step 1: find the slope of the given line segment. We have the two end points (10, 15) and (-20, 5), so the slope is m=(15-5)/(10-(-20))=1/3
the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3
step 2: find the middle point: x=(-20+10)/2=-5, y=(15+5)/2=10 (-5, 10)
so the equation of the perpendicular line in point-slope form is (y-10)=-3(x+5)
now plug in all the given coordinates to the equation to see which pair fits:
(-8, 19): 19-10=9, -3(-8+5)=9, so yes, (-8, 19) is on the perpendicular line.
try the other pairs, you will find that (1,-8) and (-5, 10) fit the equation too. (-5,10) happens to be the midpoint.
Answer:
Step-by-step explanation:
3. 
add exponents
4.
multiply exponents
5.
distribute and multiply exponents
6. 
multiply and then add exponents
7.
distribute and multiply exponents
8.
multiply and then add exponents
Answer:
x + 9
Step-by-step explanation:
Since the divisor is in the form of <em>x - c</em>, use what is called <em>Synthetic Division</em>. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
4| 1 5 -36
↓ 4 36
----------------
1 9 0 → x + 9
You start by placing the c in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em><em>,</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have NO REMAINDER. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x, and the 9 follows right behind it, giving you the other factor of x + 9.
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Answer:
The line passes through (4, -7) and (5, -10).
Step-by-step explanation:
When x = 4, y = 5 - 3(4), or 5 - 12, or -7. Thus the point (4, -7) lies on the graph. Similarly y = 5 - 3(5) = -10 when x = 5. Thus, the line also goes through (5, -10). Plot these two points and draw a line through them. Doing this will result in the desired graph.
