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valina [46]
3 years ago
14

Determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions. Afterwards, determin

e two values of xx that support your conclusion.
x = x + 3

The equation has ____.
(options are no solution, one solution, or infinite solutions)

A value of x that makes the equation false is ___, which when substituted into the equation and simplified makes the equation turn into ___ = ____.

Another value of x that makes the equation false is ___, which when substituted into the equation and simplified makes the equation turn into ___ = ___.
Mathematics
1 answer:
Anettt [7]3 years ago
5 0

Answer:

There are no solutions.

The left side of the equation will always be three less than the right side of the equation since both sides have the same variable.

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You take a three-question true or false quiz. You guess on all the questions. What is the probability that you will get a perfec
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It would be 1/8. 2 to the third is 8, and all three answers correct is one option.
4 0
4 years ago
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3 1/7 x 2 2/8 (multiply fractions)
k0ka [10]

Answer:

.214 if it is to 3 decimal places.

5 0
3 years ago
Evaluate (a + b)2 for a = 2 and b= 3.
aniked [119]

Answer:

10

Step-by-step explanation:

a = 2 and b= 3

(a + b)2

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7 0
2 years ago
Tickets to a school basketball game cost $4 for students and $7 for adults. At the end of the night, 168 tickets are sold for a
stepan [7]
4s+7a=861
s+a=168

This can be solved using either elimination or substitution. I am going to use substitution.

Solve s+a=168 for s
s=168-a

Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861

Solve for a
672+3a=861
3a=189
a=63

Substitute 63 for a in s=168-a
s=168-63=105

So, s=105 student tickets and a=63 adult tickets
3 0
3 years ago
The first answer already given, what's the second answer (in the green box)​
chubhunter [2.5K]

Solution:

Since the graph passes through the given points, (7, 20) & (-2, 11) are the solutions of the given equation <em>y = x + ?</em>.

⇒<em>(x, y)</em> = (7, 20); (-2, 11)

Substituting the variables with (7, 20),

20 = 7 + <em>?</em>

20 - 7 = <em>?</em>

<em>?</em> = 13

Similarly,

11 = -2 +  <em>?</em>

<em>?</em> = 13

∴ <em>y</em> = 13

8 0
3 years ago
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