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lana [24]
3 years ago
14

9. Reflect figure OPQR over the x-axis.

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

9) P' will be at (-3, -6)

10) T' will be at (0, -1)

11) Quadrant IV

Step-by-step explanation:

9) point P is 3 units away from the y-axis and 6 units away from the x-axis; after reflecting over x-axis it will still be the same distances away from each axis but will be in a different quadrant

10) T is at (5, 6); if translated it will be at (5-5 , 6-7) or (0, -1)

11) a point or shape moves to a new quadrant every 90 degrees

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FromTheMoon [43]
The answer is D could you give me brainlist
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3 years ago
Help me please ?????????
exis [7]
The correct answer is:  [C]:  " $4290.00 " .
_______________________________________
Explanation:
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Given:  principal, "P":  equals:  $14,300  ;
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What is the interest, "i" ? 
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  Note:  The formula:  i = P * r * t   .
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So, we plug in our given values for "P", "r", and "t", and solve for "i" (interest).
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3 years ago
What is the difference of the fractions? Use the number line to help find the answer.<br> -<br> T0
dybincka [34]

Answer:

-7/10

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A closed box has a square base with side length feet and height feet given that the volume of the box is 34 ft.³ express the sur
Deffense [45]

Answer:

\dfrac{2s^3+136}{s}

Step-by-step explanation:

Let the side length of the square base =s feet

Let the height of the box = h

Given that the volume of the box = 34$ ft^3

Volume of the box =s^2h

Then:

s^2h=34$ ft^3\\$Divide both sides by s^2\\h=\dfrac{34}{s^2}

Surface Area of a Rectangular Prism =2(lb+bh+lh)

Since we have a square base, l=b=s feet

Therefore:

Surface Area of our closed box= 2(s^2+sh+sh)

S$urface Area= 2s^2+4sh\\Recall: h=\dfrac{34}{s^2}\\$Surface Area= 2s^2+4s\left(\dfrac{34}{s^2}\right)\\=2s^2+\dfrac{136}{s}\\$Surface Area in terms of length only=\dfrac{2s^3+136}{s}

7 0
3 years ago
How To work this out ?
MrMuchimi
(a) Using the completing the square method, we need to write  into the form of  where , so
Expand to find the value of c
Notice that we get back the first two terms, the  and the .We need to get rid of the last term of '9' as the term was not in the original form. The final form will look like
Hence, 
(b)          
(c) , square root both sides      plus and minus of 2     Hence           
 
6 0
3 years ago
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