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3 years ago

In the △PQR, PQ = 39 in, PR = 17 in, and the altitude PN = 15 in. Find QR.

2 answers:

8 0

Altitude = 90* Angle

15^2+b^2 = 39^2
225+b^2 = 1521
1296 = b^2
36= b

15^2 + b^2 = 17^2
225 +b^2 = 289
64 = b^2
8 = b

36 + 8 = 44

39+17 = 56

56 is greater then 44

Triangle Inequality Theorem Proves

So QR = 44

Natali5045456 [20]3 years ago

8 0

Answer:

QR=44 or 28

Step-by-step explanation:

first you use the pythagoram theorem to find out the lenghts of RN and NQ, which lead to 36 and 8, then you add them to get 44. Put maybe QR is the hypotenuse, in which case, you get andother solution with 36 and 8, but you have to exclude NR, which gets you to 28

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A cube with sides 5 inches, and a pyramid with base edges 5 inches. What is the height, so that the volume of the cube and the p

Ostrovityanka [42]

15 inches is the height of the pyramid

Step-by-step explanation:

The volume of a cube is a³

Given a = 5 inches

→ Volume = a³

= 5³

= 5×5×5

= 125 in²

The volume of a pyramid is $\frac{1}{3} {a}^{2}h$

Given a = 5 inches , h = height of pyramid

$= > \frac{1}{3} {a}^{2} h$

$= > \frac{1}{3}(5)^{2}h$

$= > \frac{1}{3} \times 25 \times h$

$= > \frac{25}{3}h$

then,

$125 = \frac{25h}{3}$

$= > 25h = 125 \times 3$

$= > 25h = 375$

$= > h = \frac{375}{25}$

$= > h = 15$

Hence, the height of pyramid is 15 inches

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3 years ago

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sertanlavr [38]

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3 years ago

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